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castortr0y [4]
3 years ago
9

2 Points Mechanical energy is the ___ of kinetic energy and potential energy.

Physics
2 answers:
svetoff [14.1K]3 years ago
8 0

<em>H</em><em>ey</em><em>!</em><em>!</em><em>!</em>

<em>Mechanical</em><em> </em><em>energy</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em><u>sum</u></em><em><u> </u></em><em> </em><em>of</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em> </em><em>and</em><em> </em><em>poten</em><em>tial</em><em> </em><em>energy</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

Musya8 [376]3 years ago
8 0
The answer will be Kinetic energy.
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Answer:

New pressure group is N

Explanation:

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3 years ago
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A wire with radius 23 cm has a current of 7 A which is distributed uniformly through its cross sectional area. If you were to us
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Answer:

The magnetic induction of the magnetic field is  0.0005293 mT

Explanation:

Data given

I = 7 A = the total current in the wire

r = 23 cm = the radius of the wire = 0.23 meter

r' = 2cm = the measurement point, which should be inside the wire = 0.02 meter

Let's consider the current density is constant in the wire, ⇒  the current enclosed is a function of the enclosed area

I(enclosed) = Jπ r ²

we can  consider the current density  as the total current over the whole area:

I(enclosed) = I / (πr ²)  * πr' ²

I(enclosed) = (I* r'²)/ (r ²)  

with I =  total current in the wire = 7A

With r = the radius of wire = 0.23 meter

with r' = the distance of point from the center of wire  0.02 meter

We plug this into ampere's law:

∮ *B *dl =μ 0  * (I* r'²)/ (r ²)  

with B = Magnetic flux density (in Tesla) or magnetic induction

with dl = an infinitesimal element (a differential) of the curve C

with µ0 = the magnectic constant =  4π*10^−7 H/m

We can simplify this, by using an Amperian loop can write this as:

B *( 2 π r') =  μ 0  * (I* r'²)/ (r ²)  

Because the circumference of a circle is  2 π r , when we integrate over length at a distance  r ′  from the center of wire whose crossection is a circle we get  2 π r ′

When we isolate B, we get:

B = µo *(Ir'/2 π r ²)

B =  4π*10^−7 * ((7*0.02)/2*π*0.23²)

B =5.293 *10 ^-7 T  = 0.0005293 mT

The magnetic induction of the magnetic field is  0.0005293 mT

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3 years ago
HELP ME ASAP!!!! PIC IS DOWN BELOW!
vagabundo [1.1K]
I think it is B Because it sounds like the best choice
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