Suppose the roller coaster in Fig. 6-38 (h1 = 33 m, h2 = 13 m, h3 = 25) passes point A with a speed of 2.10 m/s. If the average
force of friction is equal to one fifth of its weight, with what speed will it reach point B? The distance traveled is 35.0 m
1 answer:
You might be interested in
Answer:
Image is between F and 2F. And the exact location is:
q = 10.84 cm
Explanation:
The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:
1. Image is real.
2. Image is inverted
3. Image is diminished
<u>4. Image is located between F and 2F</u>
For exact location we use the thin lens formula:
where,
f = focal length = 8 cm
p = object distance = 30.5 cm
q = image distance = ?
Therefore,
<u>q = 10.84 cm</u>