False the tsunami was up to 128 ft tall (39 meters) and flooded the city.
First write out the eqn, and balance it.
next, take 12.8g/mr of aluminium
this will give u the mols of aluminium
next, take the ratio of HCL and Al, compare and find the mols of HCL.
take the mols of HCL/mr of HCL to give u mass
doneee
Answer:
Option D. 0.115 M
Explanation:
The following data were obtained from the question:
Mass of CuSO4 = 36.8 g
Volume of solution = 2 L
Molar mass of CuSO4 = 159.62 g/mol
Molarity of CuSO4 =..?
Next, we shall determine the number of mole in 36.8 g of CuSO4.
This can be obtained as shown below:
Mass of CuSO4 = 36.8 g
Molar mass of CuSO4 = 159.62 g/mol
Mole of CuSO4 =.?
Mole = mass /Molar mass
Mole of CuSO4 = 36.8 / 159.62
Mole of CuSO4 = 0.23 mole
Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:
Mole of CuSO4 = 0.23 mole
Volume of solution = 2 L
Molarity of CuSO4 =..?
Molarity = mole /Volume
Molarity of CuSO4 = 0.23 / 2
Molarity of CuSO4 = 0.115 M
Therefore, the molarity of the CuSO4 solution is 0.115 M.
Answer:
Fatty acid
Explanation:
A fatty acid is a carboxylic acid with a long chain of 12 or more carbons.
If the molecule has no other distinguishing features, the compound is hexacosanoic acid, CH₃(CH₂)₂₄COOH.