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Ivenika [448]
3 years ago
9

Help me with this please​

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Planes two lines intersecting is called a plane

Please branleist

Yuki888 [10]3 years ago
3 0

Answer:

i think it's the first one

Step-by-step explanation:

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4. Exercise 8.1.10 (2 points)(a) Find a recurrence relation for the number of bit strings of positive lengthnthat containthe bit
nikdorinn [45]

Answer:

T0 =0, T1=0

Step-by-step explanation:

Please kindly go through the attached files for a detailed explanation.

I arranged them from the first one to the last one.

8 0
3 years ago
Construct the exponential function that contains the points (0,2) and (3,54)
erma4kov [3.2K]

The exponential function that passes through (0,2) and (3,54) is a growth function

The exponetial function is y = 2 * 3^x

<h3>How to construct the exponential function?</h3>

The points are given as:

(x,y) = (0,2) and (3,54)

An exponential function is represented as:

y = ab^x

Substitute the points in the equation

2 = ab^0 and 54 = ab^3

Solve 2 = ab^0

a = 2

Substitute 2 for a in 54 = ab^3

54 = 2b^3

Divide by 2

27 = b^3

Take the cube roots of both sides

b = 3

So, we have:

y = ab^x

This becomes

y = 2 * 3^x

Hence, the exponetial function is y = 2 * 3^x

Read more about exponential functions at:

brainly.com/question/24077767

8 0
2 years ago
Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
Several students from boxerville middle stood in a circle, evenly spaced, to play a game. If the 6th student was directly across
myrzilka [38]

Answer:

There were 14 students in the circle

Step-by-step explanation:

* Lets explain how to solve the problem

- The students stood in a circle

∴ The line joining each two opposite students is the diameter

  of the circle

- The 6th student was directly across from the 13th student

∴ The 6th student is opposite to the 13th student

- Lets count how many students between 6th student and

 13th student

∵ 7th , 8th , 9th , 10th , 11th , 12th students between the 6th

  student and 13th student

∴ There are 6 students between them

- Lets count how many students between 13th student and

 6th student

∵ 14th , 1st , 2nd , 3rd , 4th , 5th students between the 13th

  student and 6th student

∴ There are 6 students between them

∵ There are 6 students between 6th and 13th

∵ There are 6 students between 13th and 6th

∵ There are 2 students in 6th and 13th

∴ The number of the students = 6 + 6 + 2 = 14

∴ There were 14 students in the circle

8 0
4 years ago
Steve needs to take at least 24 milligrams of calcium, 15 milligrams of iron, and 16 milligrams of vitamins. Which ordered pairs
Andru [333]
Before answering that question need to know how much iron , vitamincs. etc are in brand A &B
3 0
3 years ago
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