I think with the next procedue I can help you a lot with it:
if R = 50% <span>x = Blood Alcohol Content (BAC) </span>Then <span>50= 6 e^(12.77x) </span> <span>50/6 = e^(12.77x) </span> <span>ln(50/6) = 12.77x </span> <span>x = ln(50/6)/12.77 </span> <span>x = 0.166 </span> I hope this can help you through