All categories

2 years ago

Which needs two less valence electrons to complete an octet, X+2?

Chemistry

1 answer:

Vladimir79 [104]2 years ago

7 0

Answer:

The answer to your question is Ca

Explanation:

Ne has its octet completed so, this option is wrong. Neon is stable.

C Carbon has 4 valence electrons not 2, it should lose 4 electrons to complete an octet, so this option is wrong.

N Nitrogen has 5 valence electrons not 2 , so it should gain 3 electrons to complete an octet.

Ca Calcium is the right answer it has to electrons in its outermost shell, it have to lose 2 electrons to complete an octet.

You might be interested in

How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?

Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid $\rm H_2SO_4$ is a diprotic acid. When one mole of $\rm H_2SO_4$ molecules dissolve in water, two moles of $\rm H^{+}$ ions would be produced.

$\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}$ .

On the other hand, sodium hydroxide $\rm NaOH$ is a monoprotic base. When one mole of $\rm NaOH$ formula units dissolve in water, only one mole of hydroxide ions $\rm OH^{-}$ would be produced.

$\rm NaOH \to Na^{+} + OH^{-}$ .

Note that $\rm H^{+}$ and $\rm OH^{-}$ react at a one-to-one ratio:

$\rm H^{+} + OH^{-} \to H_2O$ .

As a result, it would take $2\; \rm mol$ of $\rm OH^{-}$ to react with the $\rm 2\; mol$ of $\rm H^{+}$ that was released when $1\; \rm mol$ of $\rm H_2SO_4$ is dissolved in water. Since one mole of $\rm NaOH$ formula units could produce only one mole of $\rm OH^{-}$ , it would take $\rm 2\; mol$ of $\rm NaOH$ formula units to produce that $2\; \rm mol$ of $\rm OH^{-}$ for reacting with $1\; \rm mol$ of $\rm H_2SO_4$ .

3 0

3 years ago

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

mihalych1998 [28]

Hey there!

C₅H₅ + Fe → Fe(C₅H₅)₂

Put a coefficient of 2 in front of C₅H₅ on the left side because there is a subscript of 2 after C₅H₅ in parenthesis on the right.

2C₅H₅ + Fe → Fe(C₅H₅)₂

Fe (iron) is already balanced since there is one on each side, so we don't need to change anything for that.

This is a synthesis reaction because two reactants, C₅H₅ and Fe, are yielding a single product, Fe(C₅H₅)₂.

Hope this helps!

6 0

2 years ago

Why can some metals be extracted from compounds by heating with carbon and why can some not

pentagon [3]

Answer:

Some metals can be extracted from compounds by heating with carbon atom because they are less reactive than carbon and some metals cannot be extracted because they are more reactive than carbon atom.

Explanation: If the metal is less reactive than carbon atom so the carbon atoms make bond with oxide or other atom present with metal and the metal is free from that oxide or that element. But if the reactivity of metal is higher than carbon is unable to remove the oxide or element.

8 0

3 years ago

A vessel contains a mixture of gases. The mass of each gas used to make the mixture is known. Which of the following information

faltersainse [42]

Answer: The molar mass of each gas

Explanation:

Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.

$\text{Mole fraction of solute}=\frac{\text{Moles of solute}}{\text{Total Moles}}$

Suppose if there are three gases A, B and C.

a) $\text{Mole fraction of A}=\frac{\text{Moles of A}}{\text{ Moles of (A+B+C)}}$

b) $\text{Mole fraction of B}=\frac{\text{Moles of B}}{\text{ Moles of (A+B+C)}}$

c) $\text{Mole fraction of C}=\frac{\text{Moles of C}}{\text{ Moles of (A+B+C)}}$

moles of solute = $\frac{\text {given mass}}{\text {Molar mass}}$

Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.

8 0

2 years ago

Find the number of moles of water that can be formed if you have 138 mol of hydrogen gas and 64 mol of oxygen gas.

charle [14.2K]

2H₂₍g₎ + O₂ ₍g₎→ 2H₂O

138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O

128 mol H₂O

6 0

3 years ago

Read 2 more answers