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Alexeev081 [22]
3 years ago
14

Which of the following characteristics indicates that an atom is unstable?

Chemistry
2 answers:
qwelly [4]3 years ago
8 0

Answer:

D

Explanation:

Forming very strong bonds

ehidna [41]3 years ago
6 0

Answer:

I think is d.

Explanation:

particles that make up the nucleus are balanced. An atom is unstable (radioactive) if these forces are unbalanced; if the nucleus has an excess of internal energy. the Instability of an atom's nucleus may result from an excess of either neutrons or protons.

I'm not sure, but hope it helps.

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How is primary succession similar to secondary succession
gladu [14]

Answer:

Explanation:

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8 0
3 years ago
Read 2 more answers
1
Molodets [167]

Answer: The temperature does effect the growth of the plants. If you kept them all at different temperature and the growth was different then the temperature is definitly a factor in plant growth

Explanation:

7 0
3 years ago
How many moles of oxygen are there in 3 moles of Zn(NO3)2? (2 points)
muminat

there are 6 moles of oxygen in Zn(No3)2

4 0
2 years ago
Use bond energies from Table 10.3 in the textbook to estimate the enthalpy change (ΔH) for the following reaction. C2H2(g)+H2(g)
Digiron [165]

Answer: =176.6kJmol^{-1}

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of  C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

\Delta H= {\text {sum of bond energies of reactants}}-  {\text {sum of bond energies of products}}

\Delta H= {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

\Delta H= {1B.E(835kJmole^{-1})+2B.E(414kJmole^{-1}) +1B.E(436.4kJmole^{-1})} -  {1B.E(620kJmole^{-1})+4B.E(414kjmole^{-1})}

=176.6kJmol^{-1}







7 0
3 years ago
A certain gas at 2oC and 1.00 atm pressure fills a 4.0 container. What volume will the gas occupy at 100oC and 780 torr pressure
artcher [175]

The final volume V₂=4.962 L

<h3>Further explanation</h3>

Given

T₁=20 + 273 = 293 K

P₁= 1 atm

V₁ = 4 L

T₂=100+273 = 373 K

P₂=780 torr=1,02632 atm

Required

The final volume

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

V₂=(P₁V₁T₂)/(P₂T₁)

V₂=(1 x 4 x 373)/(1.02632 x 293)

V₂=4.962 L

6 0
3 years ago
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