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GuDViN [60]
3 years ago
5

What are some of the useful properties of current electricity

Physics
2 answers:
Nady [450]3 years ago
5 0
Conduction and heat
Hope I helped
Artist 52 [7]3 years ago
3 0
Conduction, convection and heat
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PLS THIS IS DUE IN 2 MINUTES
Tom [10]

Answer:

The toy car. An object that isn't moving has no momentum

Explanation:

3 0
3 years ago
A 1.90-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. if you ignore the weight of th
gregori [183]

Answer: The center of gravity is 1.1338 m away from the left side of the barbell

Explanation:

Length of the barbell = 1.90 m

The distance center of gravity from left = x

Mass on the left side = 25 kg

The distance center of gravity from right = 1.90 - x

Mass on the right side = 37 kg

At the balance point: m_1x_1=m_2x_2

25 kg\times x=37 kg\times (1.90-x)

x=1.1338 m

The center of gravity is 1.1338 m away from the left side of the barbell

7 0
3 years ago
Read 2 more answers
What causes the particles within the nucleus of an atom to bond together? Question 12 options: electromagnetism gravity weak nuc
monitta

Answer:

Strong nuclear force

Explanation:

The particles in the atom's nucleus bond together because there is a strong nuclear force between the protons and neutrons that attracts them to each other and binds together the nucleus.

4 0
3 years ago
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6)
tiny-mole [99]

Answer: 14.5 N

Explanation:   NEED SCRATCH PAPER: A flower pot weighing 42.0 N (newtons) is hung above a window by three ropes, each making an angle of 15.0 degrees with the vertical. What is the tension in each rope supporting the flower pot?

✓ 14.5 N

found it on the internet?

5 0
3 years ago
A torsional pendulum consists of a disk of mass 450 g and radius 3.5 cm, hanging from a wire. If the disk is given an initial an
Montano1993 [528]

To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:

\omega = 2\pi f

\omega = 2\pi (2.5)

\omega = 5\pi rad/s

The angular displacement is given as the form:

\theta (t) = \theta_0 cos(\omega t)

In the equlibrium we have to t=0, \theta(t) = \theta_0 and in the given position we have to

\theta(t) = \theta_0 cos(5\pi t)

Derived the expression we will have the equivalent to angular velocity

\frac{d\theta}{dt} = 2.7rad/s

Replacing,

\theta_0(sin(5\pi t))5\pi = 2.7

Finally

\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°

Therefore the maximum angular displacement is 9.848°

6 0
3 years ago
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