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MrRa [10]
2 years ago
6

an engineer is developing a conveyor belt to help move heavy boxes in factories. The device should be able to move boxes from th

e first floor to the second floor of a factory. The engineer is building a full- sized model to test her design.
Physics
1 answer:
Elena-2011 [213]2 years ago
4 0

Answer:

This conveyor belt should be connected to fixed pulleys in case their total effort is less than the load. But if it's not that, the belt should be connected to movable pulleys.

Explanation:

.

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A mass on a spring with k=88.7 N/m oscillates 15 times in 9.24s. what is the objects mass? unit=kg?
sweet [91]

The mass on the spring is 0.86 kg

Explanation:

The period of a mass-spring system is given by the equation

T=2\pi \sqrt{\frac{m}{k}}

where

m is the mass

k is the spring constant

In this problem, we have:

k = 88.7 N/m is the spring constant

The system makes 15 oscillations in 9.24 s: therefore, the period of the system is

T=\frac{9.24}{15}=0.62 s

Now we can re-arrange the first equation  to solve for the mass:

m=k(\frac{T}{2\pi})^2=(88.7)(\frac{0.62}{2\pi})^2=0.86 kg

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

3 0
3 years ago
A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha
Irina-Kira [14]

Answer:

pahingi po ng pic pls para masagutang kopo iyan

6 0
2 years ago
3.How can you find the velocity of the object just before impact without directly measuring it?
e-lub [12.9K]
Ugudbis sinwajdiekbdudjwndjid
7 0
3 years ago
A circular loop of wire with a radius of 20 cm lies in the xy plane and carries a current of 2 A, counterclockwise when viewed f
Zina [86]

To solve this problem we will apply the concept related to the magnetic dipole moment that is defined as the product between the current and the object area. In our case we have the radius so we will get the area, which would be

A=\pi r^2

A =\pi (0.2)^2

A =0.1256 m^2

Once the area is obtained, it is possible to calculate the magnetic dipole moment considering the previously given definition:

\mu=IA

\mu=2(0.1256)

\mu=0.25 A\cdot m^2

Therefore the magnetic dipole moment is 0.25A\cdot m^2

6 0
3 years ago
A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second, and the t
slega [8]

Answer:

The tension increases to four times its original value.

Explanation:

v = Velocity

r = Radius

m = Mass of stone

The centripetal force is

F_c=m\dfrac{v^2}{r}

The tension will balance the centripetal force

T=m\dfrac{v^2}{r}

\\\Rightarrow T\propto v^2

\dfrac{T_1}{T_2}=\dfrac{v_1^2}{v_2^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{v_1}{2^2v_1^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{1}{4}\\\Rightarrow T_2=4T_1

The new tension will be 4 times the old tension

5 0
2 years ago
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