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san4es73 [151]
3 years ago
10

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

ttached to the string and car instead of 2, then the applied force on the car will be
Physics
1 answer:
zysi [14]3 years ago
6 0

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

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To answer this question let's write the expression for electrical conductivity

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Whereby the resistance

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Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut
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Answer: a) 11.76 m/s  b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

V_{f}=V_{o}+at (1)  

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a=9.8 m/s^{2} is the acceleration due gravity

d is the height of the tower

t=0.02min=1.2 s is the time it takes to the object to reach the ground

b) Begining with (1):

V_{f}=0+at (3)  

V_{f}=at=(9.8 m/s^{2})(1.2 s) (4)  

V_{f}=11.76 m/s (5)  This is the final velocity of the object

a) Substituting (5) in (2):

(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d (6)  

Clearing d:

d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})} (7)  

d=7.056 m (8)  This is the height of the tower

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