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san4es73 [151]
3 years ago
10

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

ttached to the string and car instead of 2, then the applied force on the car will be
Physics
1 answer:
zysi [14]3 years ago
6 0

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

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Daffy Duck is standing 6.8 m away from Minnie Duck. The attractive gravitational force between them is 5.4x10-8 N. If Daffy Duck
artcher [175]

Answer:

432.78 Kg

Explanation:

From the question given above, the following data were obtained:

Distance apart (r) = 6.8 m

Force of attraction (F) = 5.4×10¯⁸ N

Mass of Daffy Duck (M₁) = 86.5 kg

Mass of Minnie Duck (M₂) =?

NOTE: Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

The mass of Minnie Duck can be obtained as follow:

F = GM₁M₂ / r²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 6.8²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 46.24

Cross multiply

6.67×10¯¹¹ × 86.5 × M₂ =5.4×10¯⁸ × 46.24

Divide both side by 6.67×10¯¹¹ × 86.5

M₂ = 5.4×10¯⁸ × 46.24 / 6.67×10¯¹¹ × 86.5

M₂ = 432.78 Kg

Therefore, the mass of Minnie Duck is 432.78 Kg

8 0
3 years ago
You apply a potential difference of 5.70 v between the ends of a wire that is 2.90 m in length and 0.654 mm in radius. the resul
photoshop1234 [79]
1) First of all, let's find the resistance of the wire by using Ohm's law:
V=IR
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega

2) Now that we have the value of the resistance, we can find the resistivity of the wire \rho by using the following relationship:
\rho =  \frac{RA}{L}
Where A is the cross-sectional area of the wire and L its length.
We already have its length L=2.90 m, while we need to calculate the area A starting from the radius:
A=\pi r^2 = \pi (0.654\cdot 10^{-3}m)^2=1.34 \cdot 10^{-6}m^2

And now we can find the resistivity:
\rho =  \frac{RA}{L}= \frac{(0.32 \Omega)(1.34 \cdot 10^{-6}m^2)}{2.90m}=  1.48 \cdot 10^{-7}\Omega \cdot m
7 0
3 years ago
A 20 newton force moves an object southeast. What two properties of force have been described?
Galina-37 [17]

Answer:

The answer is C

Explanation:

Force is a vector quantity so it has both magnitude and direction. The question shows 20N act as magnitude and Southeast act as direction.

7 0
3 years ago
Which robotic missions studied Venus?
frosja888 [35]
The first successful flyby of Venus was performed by NASA's Mariner 2 spacecraft on 14 December 1962, following failed attempts by both the Soviet Union and the USA. The first successful landing was the Soviet Venera 4 lander, which touched down on the surface on 18 October 1967
6 0
3 years ago
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Has anyone done the Physical Science B- Forces and Motion Unit Test?? If so could you please help me
Sedbober [7]
I haven't, but I'm sure @Porshia has!
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