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3 years ago

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If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

ttached to the string and car instead of 2, then the applied force on the car will be

1 answer:

zysi [14]3 years ago

6 0

Given that,

Mass of each washer = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer $m= 4.9\times10^{-3}\ Kg$

So, Mass of two washers is

$M=2\times m$

Put the value of m

$M=2\times4.9\times10^{-3}\ k$

$M=0.0098\ Kg$

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

$F=mg$

Put the value into the formula

$F=4\times4.9\times10^{-3}\times9.8$

$F=0.192\ N$

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

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Veronika [31]

Answer:

(A) Speed will be $44.18\times 10^4m/sec$

(b) Change in kinetic energy = $1560\times 10^{-19}$

Explanation:

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Acceleration of the proton $a=2.50\times 10^{12}m/sec^2$

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(b) Initial kinetic energy $KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2$

Final kinetic energy $KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2$

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3 years ago

If the relative humidity is 25 nd the saturation mixing ratio is 24g/kg, what is the mixing ratio?

levacccp [35]

The mixing ratio is 6.

To find the answer, we have to know about the mixing ratio.

<h3>What is mixing ratio?</h3>

The mixing ratio must be calculated in a complex manner.
A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,

$Rh=\frac{w}{w_s} *100$

where; w is the mixing ratio and w(s) is the saturation mixing ratio.

In our question, it is given that,

$Rh=25\\w_s=24$

Thus, the mixing ratio will be,

$w=\frac{Rh*w_s}{100} =\frac{25*24}{100}=6$

Thus, we can conclude that, the mixing ratio is 6.

Learn more about mixing ratio here:

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