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boyakko [2]
3 years ago
15

Jane believes that plate tectonics is a theory, and Mario believes it is a law. Which of the following best supports Jane’s argu

ment?
A. Plate tectonic theory specifies how fast the plates may have moved in the past.

B. Plate tectonic theory gives a precise prediction of the direction of plate tectonics.

C. Plate tectonic theory explains why the outer layers of the Earth move and change.

D. Plate tectonic theory provides a means to calculate exactly where and when the plates will move.
Physics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

its d

Explanation:

i did this and got it right

natima [27]3 years ago
6 0
Answer: D
Hope this helps at least a little bit :)
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A coaxial cable carries a current I =0.02A through a wire of radius Rw=.2mmin one direction and an identical current through the
Anna [14]

Answer:

a)  B = 10⁻¹ r , b)  B = 4 10⁻⁹ / r , c) B=0

Explanation:

For this exercise let's use Ampere's law

            ∫ B. ds = μ₀ I

Where I is the current locked in the path. Let's take a closed path as a circle

          ds = 2π dr

          B 2π r = μ₀ I

          B = μ₀ I / 2μ₀ r

Let's analyze several cases

a) r <Rw

Since the radius of the circumference is less than that of the wire, the current is less, let's use the concept of current density

          j = I / A

For this case

         j = I /π Rw² = I’/π r²

         I’= I r² / Rw²

The magnetic field is

        B = (μ₀/ 2π) r²/Rw²   1 / r

        B = (μ₀ / 2π) r / Rw²

calculate

        B = 4π 10⁻⁷ /2π   r / 0.002²

        B = 10⁻¹ r

b) in field  between   Rw <r <Rs

In this case the current enclosed in the total current

      I = 0.02 A

      B = μ₀/ 2π   I / r

      B = 4π 10⁻⁷ / 2π  0.02 / r

      B = 4 10⁻⁹ / r

c) the field outside the coaxial Rs <r

In this case the waxed current is zero, so

       B = 0

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3 years ago
How much work is done using a 500 W microwave for 5 minutes
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Power = work done/time

work done = power x time

                  = 500x5x60

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2. A person standing at
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God is good man what can you say but its 18.66x30301=362728
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There are 10⁹ picoseconds in 1 Ms

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1 Ms = 10⁻³ s

so the number of picoseconds in one Ms=(10⁻³ s/1 Ms) * (10¹² Ps/ 1 s)=10⁹

Thus there are 10⁹ picoseconds in 1 Ms

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A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c
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When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

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2.6 = (vf - 0)/4
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Then W = 1/2*(2100 kg)*(10.4 m/s)2
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