When an object gets heated by a temperature ΔT energy needed, E = mcΔT
Here energy is given E = 2050 J
Mass of object = 150 g
Change in temperature ΔT = 15 
= 15 K
a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.
So heat capacity = E/ΔT = 2050/15 = 136.67 J/K
b) We have E = mcΔT
c = 
So object's specific heat = 911.11 J/kgK
The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²
<h3>What is gravitational constant?</h3>
According to Sir Isaac Newton's rule of universal gravitation and Albert Einstein's theory of general relativity, the gravitational constant, indicated by the capital G, is an empirical physical constant that is used to calculate the gravitational effects.
<h3>According to the given information:</h3>
mass of object = 10kg
gravitational constant = 6.67 x 10^-11
radius of earth = 6.3 x 10^6
we know that:
acceleration due to gravity = GM/R²
= ((6.67 x 10^-11)*10)/(6.3 x 10)²
Solving this we get :
42.02 x 10^-16 m/s²
The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²
To know more about acceleration due to gravity visit:
brainly.com/question/13860566
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Triangular Prism
Rectangular Prism
Octagonal Prism
The image formed by a concave mirror with the object placed at the center of curvature is real inverted and formed at the center of curvature. Using the ray diagram a ray from the top of the object to the mirror through f then reflected parallel to the principal axis,then the ray through the center of curvature reflected through the same point both intersect at a plane through center curvature and perpendicular to the principal axis. The point of intersection forms the top of the image and the center of curvature forms the bottom. Therefore, the correct choices are : real and inverted
