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vodka [1.7K]
3 years ago
15

A sprinter accelerates from rest to 10.0 m/s in 1.35 s l. What is her acceleration?

Physics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

dsfsdfgfdsggfgsgsfsfgfsgffsfgfgfgf

Explanation:

sgdfggsfdsgfgsgsmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

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All else equal, the payback period for a project will decrease whenever the_______.
telo118 [61]

Answer:

(B) cash inflows are moved earlier in time.

Explanation:

The payback period stated time-frame during which the initial amount of investment should be recovered. It is expressed in the year form

The formula to compute the payback period is shown below:

Payback period = Initial investment ÷ Net cash flow

where,  

The net cash flow = annual net operating income + depreciation expenses

The payback period of the project decreases when the accumulated starting year cash flows increases that results the movement of the cash inflows earlier in time

3 0
3 years ago
Read 2 more answers
A researcher measures the thickness of a layer of benzene (n = 1.50) floating on water by shining monochromatic light onto the f
NNADVOKAT [17]

Answer:

Explanation:

This problem relates to interference of light in thin films .

The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index  is as follows.

2nt = (2n+1) λ / 2  , n is refractive index of thin layer , t is its thickness ,  λ is wavelength of light .

2 x 1.5 t = λ / 2 , if n = 0 for minimum thickness.

2 x 1.5 t = 600 / 2 nm

t = 100 nm .

5 0
3 years ago
Carbon-14 has a half-life of 5,700 years. How long will it take for 6.25% of the Carbon-14 to be remaining?
IRISSAK [1]

Answer:

22,800 years

Explanation:

Half life equation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is time,

and T is the half life.

0.0625 = (½)^(t / 5700)

log 0.0625 = (t / 5700) log 0.5

4 = t / 5700

t = 22,800

It takes 22,800 years.

4 0
3 years ago
Which of the following best describes a completely elastic collision?
IRISSAK [1]
The kinetic energy before equals K after
3 0
3 years ago
Which one of the following temperatures (in °C) is equivalent to 294 K?
vaieri [72.5K]

Answer:

21

Explanation: its actually 20.85 but i guess they round to 21

5 0
2 years ago
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