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fomenos
3 years ago
7

How many grams are in 2.4 moles of NH4?

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer: 43.2 grams

Explanation:

Given that,

Amount of moles of NH4 (n) = 2.4

Mass of NH4 in grams (m) = ?

For molar mass of NH4, use the molar masses of:

Nitrogen, N = 14g;

Hydrogen, H = 1g

NH4 = 14g + (1g x 4)

= 14g + 4g

= 18g/mol

Since, amount of moles = mass in grams / molar mass

2.4 mole = m / 18g/mol

m = 2.4 mole x 18g/mol

m = 43.2g

Thus, there are 43.2 grams in 2.4 moles of NH4.

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Help I need to show work!
lubasha [3.4K]

Answer:

a. Combustion.

b. m_C=3.057gC

c. m_H=3.67gH

Explanation:

Hello.

a. In this case, given the reaction by which propane is converted into carbon dioxide and water:

C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O

It is known as a combustion reaction since it is about a fuel (here propane) which is burnt by the oxygen contained in the air (21%).

b. Since the carbon dioxide contains all the carbon in the products based on the law of conservation of mass, the yielded grams are computed via a mole mass relationship:

m_C=11.21gCO_2*\frac{12gC}{44gCO_2}=3.057gC

Since 44 grams of carbon dioxide contain 12 grams of carbon.

c. As well as b., all the hydrogen is  given off in form of water, thus, the required mass turns out:

m_H=33.0gH_2O*\frac{2gH}{18gH_2O}=3.67gH

Since 18 grams of water contain 2 grams of hydrogen.

Best regards.

6 0
3 years ago
HELP HELP HELP
PilotLPTM [1.2K]
I believe it is D my good friend.
6 0
3 years ago
Read 2 more answers
8. The best way to obtain pure, solid household salt from a solid mixture of household salt and sand is to:
dedylja [7]

The best way to obtain pure, solid household salt from a solid mixture of household salt and sand is to "add water, stir, filter and evaporate the filtrate".

<u>Option: C</u>

<u>Explanation:</u>

The salt and sand can be separated on the basis of solubility, as we know the salt is chemically known as sodium chloride, which have good solubility in water. The most general method is the mixture is taken into a flask or beaker and water is added with stirring, where salt get dissolved and sand remain as it is, because NaCl is capable enough to form hydrogen bonding with water, while sand have absence of such property. Then this solution containing insoluble sand is filtered by using filter paper. The sand is received in filter paper while filtrate in beaker is evaporated by boiling it in order to receive salt as residue.

8 0
3 years ago
in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
kolezko [41]

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5

mol of element G :

\tt mol=\dfrac{4}{16}=0.25

mol ratio A : G = 0.5 : 0.25 = 2 : 1

4 0
3 years ago
Ethanoic acid, CH3COOH, ionizes to form an ethanoate ion (CH3COO-) in aqueous solution. what else does it form? is it a monoprot
barxatty [35]

Ethanoic acid ionizes in aqueous solutions to form two ions which are CH_3COO^- and H^+

<h3>Ionization of ethanoic acid</h3>

Ethanoic acid goes by the chemical formula CH_3COOH.

In aqueous solutions, it ionizes as a monoprotic acid according to the following equation:

CH_3COOH ---- > CH_3COO^- + H^+

A monoprotic acid is an acid that is able to donate only a proton. Hence, ethanoic acid is said to be monoprotic because it ionizes in aqueous solutions to produce a single H^+

More on ethanoic acid can be found here: brainly.com/question/9991017

#SPJ1

8 0
2 years ago
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