Answer:
37.15 h.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction <em>(k = 2.4 x 10⁻² h⁻¹)</em>.
t is the time of the reaction <em>(t = ??? day)</em>.
a is the initial concentration of nuclides <em>(a = 100 %)</em>.
(a-x) is the remaining concentration of nuclides <em>(a - x = 100% - 59% = 41.0 %)</em>.
<em>∴ kt = lna/(a-x)</em>
(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).
(2.4 x 10⁻² h⁻¹)(t) = 0.8916.
<em>∴ t </em>= (0.8916)/(2.4 x 10⁻² h⁻¹) = <em>37.15 h.</em>
Hence they got seven electrons in ground state
19 protons and 19 electrons but neutrons are vary
<h3>
Answer:</h3>
2.0 mol C₆H₁₂O₆
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆