Psychology is a A) science B) philosophy C) theory D) opinion

Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collid

jarptica [38.1K]

Answer:

Explanation:

Using the law of conservation of momentum;

$m_1 u_1+m_2u_2 = m_1v_1+m_2v_2$

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

$m_1$ = mass of cart X

$m_2$ = mas 9f cart Y

$u_1$ = velocity of cart X (before collision)

$u_2$ = velocity of cart Y (before collision)

$v_1$ = velocity of cart X (after collision)

$v_2$ = velocity of cart Y (after collision)

So;

$m(u_1+0) =(m_1v+m_2)v$

because the mass is identical and v represents the velocity of both carts.

Now;

$u_1$ = 2 m/s

$u_2$ = 0 ( at rest)

∴

m(2) = (2m)v

v = 1 m/s

Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.

8 0

2 years ago

Newton's 2nf law of motion States that

lapo4ka [179]

Answer:

B (force = mass X acceleration)

Explanation:

The acceleration of an object depends on the mass of the object and the amount of force applied. His second law defines a force to be equal to change in momentum (mass times velocity) per change in time.

Formula: F = m x a

6 0

2 years ago

A 49.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.584 and 0.399,

NISA [10]

Answer:

(a) Force must be grater than 283.87 N

(B) Force will be equal to 193.945 N

Explanation:

We have given mass of the crate m = 49.6 kg

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of static friction $\mu _s=0.584$

Coefficient of kinetic friction $\mu _k=0.399$

(a) Static friction force is given by $F_S=\mu _smg=0.584\times 49.6\times 9.8=283.8707N$

So to just start the crate moving we have to apply more force than 283.87 N

(B) This force will be equal to kinetic friction force

We know that kinetic friction force is given by $F_k=\mu _kmg=0.399\times 49.6\times 9.8=193.945N$

3 0

2 years ago

Ok these are my last points say hi if u want brainliest

lawyer [7]

Answer:

Hi

Explanation:

5 0

3 years ago

Read 2 more answers

A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment

snow_lady [41]

Answer:

18 radians

Explanation:

The computation is shown below:

As we know that

Torque = Force × Moment arm

= 1N × 1M

= 1N-M

Torque = $I\alpha$

$\alpha = \frac{torque}{I}\\\\= \frac{1}{100}\\\\= 0.01 rad/s^2$

Now

$\theta = w_ot + \frac{1}{2} \alpha t^2\\\\w_o = 0\\\\\theta = 0 \times 60 + \frac{1}{2} \times 0.01 \times 60^2\\\\= 18\ radians$

Here t = 1 minutes = 60 seconds

3 0

2 years ago

Psychology is aA) science B) philosophy C) theory D) opinion