The mass of the ethylene glycol used is 14.26 g
<h3>What is the freezing point?</h3>
The freezing point is the temperature at which a liquid is converted to a solid.
Given that;
ΔT = 0.0°C - ( -4.3°C) = 4.3°C
ΔT = 4.3°C
But we know that
ΔT = k m i
m = ΔT/k i
m = 4.3°C/1.86 °C/m * 1
m = 2.3 m
Now;
Let the mass of ethylene glycol be m
Molar mass of ethylene glycol = 62 g/mol
Mass of solvent = 100.0 g or 0.1 Kg
Then;
2.3= m/62/0.1
2.3 = m/62 * 0.1
m = 2.3 * 62 * 0.1
m = 14.26 g
Learn more about freezing point:brainly.com/question/3121416?
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The percent by mass : 6.3%
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
mass of potassium nitrate = 8.4 g⇒solute
- mass of solution = mass of solute+mass of solvent(water)
mass of potassium nitrate + mass of water = 8.4 g + 125 g =133.4 g
Percent by mass of the solute :
I think the copper could melt to cup and the water would smell like rust
Add up all the grams to get 9.96, then divide the amount if each element by the total;
4.56 of Pb divided by 9.96 = 0.4578313 now multiply by 100 and get 45.8% of Pb, then do the same for the rest of the elements, hope this helped <3
Since the acid and base react in a one to one ratio, you can use the equation M1V1 = M2V2 to solve for M2, or the molarity of NaOH.
M1 = 0.9 M HCl
V1 = 200.0 mL HCl
M2 = ?
V2 = 23.9 mL NaOH
(0.9 M)(200.0 mL) = M2(23.9 mL) —> M2 = 7.53 M NaOH