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Bess [88]
2 years ago
6

Abigail runs one complete lap (400m) around the track, while Gabi runs a 50 meter dash in a straight line. Which runner had a gr

eater displacement?
Physics
2 answers:
MissTica2 years ago
5 0

Answer:

The distance of one lap on this track from the start line to the finish line is 400 meters. Two laps around the track is 800 meters, half a lap is 200 meters, and so on.

    Remember, displacement is the direction from the starting point and the length of a straight line from the starting point to the ending point. If a runner was going to run 400 meters (one lap around the track), they would start and stop at the same place on the track. Therefore, their displacement would be 0.

 

Explanation:

hope this helped

Ipatiy [6.2K]2 years ago
4 0

Answer:

\boxed {\boxed {\sf Gabi \ had \ greater \ displacement}}

Explanation:

Displacement is the change in the position of an object.

Abigail runs a complete lap around the track, which is 400 meters. Even though she ran 400 meters, she has <u>no displacement.</u> If she starts and ends at the same spot, there is no change in position.

Gabi runs a 50 meter dash in a straight line. Gabi has <u>50 meters of displacement</u>. She runs in a straight line and is 50 meters away from where she began.

While Abigail ran the farther distance, <u>Gabi had the greater displacement.</u>

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A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
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Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

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Rearrange for s

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Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

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Rearrange for t

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