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4 years ago

Controlling voluntary skeletal muscles is a function of the __________ nervous system.

Physics

2 answers:

Brut [27]4 years ago

5 0

Answer:

Your answer is SOMATIC :)

The somatic nervous system is the part of the peripheral nervous system associated with the voluntary control of body movements and skeletal muscles.

marshall27 [118]4 years ago

4 0

The answer would be C. Controlling voluntary skeletal muscles is a function of the SOMATIC nervous system.

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Which is an example of a physical change?

Lilit [14]

Answer :
b - cake baking

explanation :
because the rest of the options are changing due to chemical reactions , when you bake a cake your developing it’s actions by touching it physically

6 0

3 years ago

Read 2 more answers

While camping in Denali National Park in Alaska, a wise camper hangs his pack of food from a rope tied between two trees, to kee

Crank

The tension in each of the ropes is 625 N.

Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.

Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,

$2T sin\theta = 50 N$ ......(1)

Calculate the value of sinθ using the right angled triangles from the diagram.

$sin\theta =\frac{0.06 m}{1.5 m} =0.04$

Substitute the value of sinθ in equation (1) and simplify to obtain T.

$2T sin\theta = 50 N\\ T= \frac{50 N}{2 sin\theta}=\frac{50 N}{2*0.06} = 625 N$

Thus the tension in the rope is 625 N.

4 0

4 years ago

A heat pump that operates on the ideal vapor-compression cycle with refrigerant-134a is used to heat a house. The mass flow rate

Savatey [412]

(a)

Use â€œsaturated refrigerant-134a pressure tableâ€, to find $ , h , and of refrigerant-134a, at 320kPa (P) .

$h_{1} h_{g}$ = 251.93kJ/kg

$s_{1} (s_g}$ ) =0.93026 kJ/kg-K

$v_{1}(v_{g})$ =0.063681 m/kg

we solve $h_{6}$ ,

$h_{6}$ = 282.62 kj/kg

$h_{3} (h_{f)}$ = 127.25 kJ/kg

We use this formula for finding $Q_{n}$

$Q_n} =( h_{2} - h_{3} )$

= 38.8 kw

(b)

Find the COP of the heat pump ( $COP_{R}$ ) .

( $COP_{R}$ ) = $q_{L} /w_{in}$

$COP_{R}$ = (282.62 -127.25) / (282.62-251.93)

= 5.06

What is evaporator pressures ?

Valves for regulating evaporator pressure

Although the compressor suction pressure may be lower, evaporator pressure regulation (EPR) valves can be employed in the suction line to prevent the evaporator pressure from dropping below a set or controlled value.

An EPR valve is used for the following tasks:

1. Prevent potential damage to a liquid chilling evaporator from the liquid freezing.

2. Prevent frost from accumulating on an air-cooling evaporator when it is near freezing point or when operation cannot be interrupted by a brief failure.

3. Permit the operation of two or more evaporators with the same compressor at various load temperatures.

4. Vary the evaporator pressure in accordance with a fluctuating load that is managed by the load temperature.

Learn more about evaporator pressures visit this link:

brainly.com/app/ask?q=What+is+evaporator+pressures+

#SPJ4

7 0

1 year ago

Another circuit question. So far I've incorrectly done this one 3 out of 5 times lol

marta [7]

Hope this helps you.