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3 years ago

How does a substitution mutation affect a cell?

1 answer:

6 0

It refers to a base substitution when the change in nucleotide changes the amino acid coded for by the affected codon

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A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 25° above the horizo

mars1129 [50]

Answer:

a) $y=17.6m$

b) $v_{x}=39.87m/s\\v_{y}=-28.05m/s$

Explanation:

From the exercise we got our initial data

$v_{o}=44m/s\\\beta =25\\x=190m$

a) To find maximum height we know that at that point $v_{y}=0$

$v_{y} ^{2} =v_{oy} ^{2} +2a(y-y_{o} )$

$0=(44sin25)^{2} -2(9.8)y$

Solving for y

$y=\frac{(44sin25)^{2} }{2(9.8)} =17.6 m/s$

b) Since we know that the ball strikes the fairway 190 m away

$x=v_{ox}t\\ 190=44cos25t$

Solving for t

$t=4.76s$

Now, we can calculate the speed of the ball in both axes

$v_{x}=44cos25=39.87m/s$

$v_{y}=v_{oy}+at$

$v_{y}=44sin25-(9.8)(4.76)=-28.05m/s$

The negative sign means the direction of the ball at that point.

5 0

4 years ago

Light shines through a single slit whose width is 5.6 × 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a

Mrac [35]

Answer:

462 nm

Explanation:

Given: width of the slit, d = 5.6 × 10⁻⁴ m

Distance of the screen, D = 4.0 m

Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m

First dark fringe means n =1

Wavelength of the light, λ = ?

$\beta = \frac{\lambda D}{d}\\ \Rightarrow \lambda = \frac{d \beta}{D} =\frac{5.6\times 10^{-4} \times 3.3 \times 10^{-3}}{4.0} = 4.62 \times 10^{-7}m = 462 nm$

5 0

3 years ago

A supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 100 m above the

pishuonlain [190]

The package should be dropped 678 m short of the target.

A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.

The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.

Use the equation,

$y=\frac{1}{2} gt^2$

Write an expression for t, the time taken for the package to fall through y.

$t^2=\frac{2y}{g}$

Substitute 100 m for y and 9.81m/s² for g.

$t^2=\frac{2y}{g}\\ =\frac{2(100m)}{9.81m/s^2} \\ =20.39s^2\\ t=4.52s$

In the time t the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.

Therefore, the horizontal distance traveled by the package is given by,

$x=vt\\ =(150m/s)(4.52s)\\ =678m$

If the package is released 678m before the target, the package would reach the scientists working in Greenland.

6 0

4 years ago

Energy is ____________________ when light is directed upward into the night sky and lost into ____________________.

lisov135 [29]

1: Lost (?)
2: Space (?)
........................

7 0

4 years ago

Runner x starts 50 feet in front of runner z and moves with a velocity of 8.0 m/s. At what speed would runner z have to run to c

Mariulka [41]

Answer:

15.625

Explanation:

8 0

3 years ago