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OleMash [197]
3 years ago
9

Can I have an anime weirdo friend that's a girl pwease cuz guys are mean and don't understand. I'm a 16 yo guy​

Physics
2 answers:
saveliy_v [14]3 years ago
7 0
Lol lol lol 2348 lol lol wywiwi
Alisiya [41]3 years ago
4 0

Answer:

Girls, we found one.

The "uwu pwease pwotect me, waifu" 'nice guy' that tries convincing naive girls to send inappropriate pictures within 2 hours of knowing them because he "in love" them.

The reality of the situation is the dude is very desperate and wants to project their anime girl fantasies onto a girl that pities them because "gwuys are mwean" to them.

Step-by-step explanation:

You're 16, kid. Two years until you're 18. Just say you want a weeb girl/friend. no need to try and draw pity from little girls and use that to manipulate them. If you said this when you were 12, it would be excusable. But you're 16. If you want to attract girls, don't use pity. Or try to type words in a cutesy manner, that's just very unattractive and makes you seem desperate.

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A railroad tank car contains milk and rolls at a constant speed along a level track. The milk begins to leak out the bottom. The
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option C

Explanation:

The correct answer is option C                        

There is no external force acting in the system hence the momentum will be conserved.                                    

As the milk is leaking out of the tank mass of the tanker is decreasing.

When the mass of the container will decrease to  conservation the momentum speed of the container will have to be increased.

So, the car carrying milk will speed up.

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Why is a rotting apple a reaction in which energy is neither absorbed nor released?
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7 0
3 years ago
Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem
statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

x=x_o+v_1t    (1)

xo = 10 km

v1 = 55km/h

car 2:

x'=v_2t    (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}

t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s

The position in which both cars coincides is:

x=(55km/h)(0.33h)=18.33km

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