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Valentin [98]
2 years ago
13

The rest mass of a proton is 1.673 × 10-27 kg. The relativistic mass of a proton when its velocity is 0.8c is approximately

Physics
1 answer:
sergiy2304 [10]2 years ago
7 0
Do u know the formula
m= \frac{ m_{0} }{ \sqrt{1- \frac{ v^{2} }{ c^{2} } } }
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Which statement BEST describes acceleration?
Mashutka [201]
C) Acceleration is the rate of change of velocity of an object. Velocity is the speed and direction of an object so acceleration is used to describe the rate of change. I hope this helps!!
3 0
3 years ago
A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
Hoochie [10]

The acceleration of the box is approximately 1 m/s^2

Explanation:

According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:

\sum F = ma

where

\sum F is the net force

m = 12.0 kg is the mass of the box

a is the acceleration

The net force can be written as

\sum F = F_a - F_f

where

F_a = 20 N is the applied forward force

F_f=9.0 N is the friction force

Combining the two equations,

F_a-F_f=ma

And solving for the acceleration,

a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
Things that are moving out of phase create an interference pattern<br> TURE or False??
Margarita [4]

Answer:

false

Explanation:

I think I am right with this

8 0
3 years ago
What happens when a boxer doesn't make weight?
ryzh [129]
They would just have to box in a higher weight class
6 0
3 years ago
A basketball player makes a jump shot. The 0.630-kg ball is released at a height of 1.80 m above the floor with a speed of 7.09
N76 [4]

mass of the ball m = 0.63 kg

initial height h = 1.8 m

final height h ' = 3.03 m

initial speed v = 7.09 m / s

final speed v ' = 4.21 m / s

Let the work done on the ball by air resistance W = ?

we know from law of conservation of energy ,

total energy at height h + work done by air = total energy at height h '

  mgh + ( 1/ 2) mv^ 2 + W = mgh ' + ( 1/ 2) mv'^ 2

0.630*9.8*1.8 + 0.63*7.09^2 + W = mgh ' + ( 1/ 2) mv'^ 2

From there you can find W

if there is negative sign indicates it work opposite direction to motion

6 0
2 years ago
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