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Fine particles, ground level ozone, sulfur dioxide, nitrogen dioxide, lead
<h3><u>Answer;</u></h3>
= 12.5 Moles of CaSO3
<h3><u>Explanation</u>;</h3>
The reaction between CaCO3 and SO2 is given by the equation.
CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)
The mole ratio between CaCO3 and SO2 is 1 : 1;
1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2
Therefore;
<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>
Oceans are the most common of course
Answer : The volume of stock solution needed are, 12.5 mL
Explanation :
Formula used :
where,
are the initial molarity and volume of copper (II) chloride.
are the final molarity and volume of stock solution of copper (II) chloride.
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution needed are, 12.5 mL
