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FromTheMoon [43]
3 years ago
6

How does charging by conduction work?

Physics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.

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If the sun suddenly ceased to shine, how long would it take earth to become dark? you will have to look up the speed of light in
sleet_krkn [62]
We are 8 light minutes from the sun. That means two things, we see the sun as it was 8 minutes ago, and we WOULD continue to see the sun for 8 minutes after it disappeared.
3 0
3 years ago
Two 0.20-kg balls, moving at 4 m/s east, strike a wall. Ball A bounces backwards at the same speed. Ball B stops. Which statemen
muminat

Answer:

Option A

Explanation:

From the question we are told that:

Mass m=0.20kg

Velocity v=4m/s

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum

 M_{a1}=mV

 M_{a1}=0.2*4

 M_{a1}=0.8

Final Momentum

 M_{a2}=-0.8kgm/s

Therefore

 \triangle M_a=-1.6kgm/s

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum

 M_{b1}=mV

 M_{b1}=0.2*4

 M_{b1}=0.8

Final Momentum

 M_{b2}=-0 kgm/s

Therefore

 |\triangle M_a|>|\triangle Mb|

Option A

4 0
3 years ago
Which term is a scalar quantity?
balu736 [363]
Vector quantities have both magnitude and direction. Distance is a scalar quantity. It refers only to how far an object has traveled. For example, 4 feet is a distance; it gives no information about direction.
7 0
3 years ago
Read 2 more answers
Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and
dexar [7]

Kepler’s
third law formula: T^2=4pi^2*r^3/(GM)

We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496
× 10^11 m)^3/((6.674× 10^-11N*m^2/kg^2)*(365.26days)^2)

M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work
with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel
them:

1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/(
86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The
closest answer is 1.99
× 10^30

(it may vary
a little with rounding – the difference is less than 1%)


8 0
3 years ago
Read 2 more answers
What should be done to lift the same load by applying less effort on an inclined plane​
Scorpion4ik [409]

Answer:

Reduce the friction at the surface

Explanation:

If you can reduce the friction between the load and the plane less effort will be required as you are not having to apply effort to overcome friction.

5 0
2 years ago
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