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Juliette [100K]
3 years ago
7

Use the drop-down menus to complete the statements. are pure substances that cannot be broken down into a simpler form. are unit

s of two or more atoms. are the smallest possible particles of an element. are pure substances made of two or more atoms of different elements.
Physics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer: Please see below

Explanation:

Are pure substances that cannot be broken down into a simpler form---- Element

are units of two or more atoms---- Molecule

are the smallest possible particles of an element---- an Atom

are pure substances made of two or more atoms of different elements---- Compound

An atom is the smallest unit of  matter that consists of protons, neutrons and electrons. Eg the element, helium, contains atoms with two protons in the nucleus.

Eg of element, we have carbon, hydrogen, helium

Eg of a compound--- Ammonia

Eg of a molecule-----H2O (water),C6H12O6 (glucose)

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Which "spheres" are interacting when water evaporates from plants
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A particle moves along a straight path through a displacement d = 2.5i + cj while a force F = 8.5i + -8.5j acts on it. The displ
Zanzabum

Answer:

Explanation:

Work is defined as the scalar product of force and distance

W=F•d

Given that

F = 8.5i + -8.5j. +×-=-

F=8.5i-8.5j

d = 2.5i + cj

If the work in the practice is zero, then W=0

therefore,

W=F•ds

0=F•ds

0=(8.5i -8.5j)•(2.5i + cj)

Note that

i.i=j.j=k.k=1

i.j=j.i=k.i=i.k=j.k=k.j=0

So applying this

0=(8.5i -8.5j)•(2.5i + cj)

0= (8.5×2.5i.i + 8.5×ci.j -8.5×2.5j.i-8.5×cj.j)

0=21.25-8.5c

Therefore,

8.5c=21.25

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7 0
3 years ago
A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F-> of magnitude 4.8
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Answer

4.8 N

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6 0
3 years ago
Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
Oksanka [162]

Explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

v=\dfrac{c}{\mu}....(I)

Where, \mu = index of refraction

c = speed of light

Put the value into the formula

v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.63}

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(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.50}

v=2\times10^{8}\ m/s

Hence, This is the required solution.

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3 years ago
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