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prohojiy [21]
3 years ago
7

Un automóvil lleva una velocidad inicial de 20 km/h al norte y a los 4 segundos su velocidad es de 50 km/h

Physics
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer:

Desplazamiento

Explanation:

oksian1 [2.3K]3 years ago
6 0
La unidad de aceleración es en metros por segundo al cuadrado m/s2.

Asi que, primero convertí los km/h a m/s:

50 km/h = 13.889 m/s
20 km/h = 5.556 m/s

Y los sustituís en la fórmula de aceleración:

(a = Δv / Δt). En la misma, “a” es la aceleración, “Av” es la variación de la velocidad y “At” es el tiempo que hay en esa variación.

a = (13.889 - 5.556) / 4 segs
a = 8.333 / 4
a = 2.08325 m/s2

Espero te funcione!

Marca mi respuesta como brainliest porfa!!!

Suerte :)
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The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a
SashulF [63]

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm=1900\times 10^{-9}m

Where 1nm=10^{-9} m

\lambda_2=400nm=400\times10^{-9}m

\lambda_1=700nm=700\times 10^{-9}m

We have to find  the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

\theta=sin^{-1}(\frac{m\lambda}{d})

Using the formula

m=1

\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})

\theta=21.62^{\circ}

Now, m=2

\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})

\theta_2=24.90^{\circ}

\Delta \theta=\theta_2-\theta_1

\Delta \theta=24.90-21.62

\Delta \theta=3.28^{\circ}

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

6 0
3 years ago
If the output current for the transformer is 1.8 A, find the input current.
Iteru [2.4K]
The answer is 3.16 B
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It has been argued that power plants should make use of off-peak hours (such as late at night) to generate mechanical energy and
Trava [24]

Answer:

Explanation:

kinetic energy = 14.1 MJ = 14.1 x 10⁶ J

Let radius of flywheel be r .

volume of flywheel = π r² x t where t is thickness

= 3.14 x r² x .113 m³

= .04 r² m³

mass = volume x density

= .04 r² x 7800 = 312.73 r²kg

moment of inertia I = 1 / 2 mass x radius²

= .5 x 312.73 r² x r²

= 156.37 r⁴ kg m²

angular velocity ω = 2π x 93/60

= 9.734 rad /s

kinetic energy = 1/2 Iω² where ω is angular velocity

= .5 x 156.37 r⁴ x 9.734²

= 7408.08 r⁴

Given

7408.08 r⁴ =  14.1 x 10⁶

r⁴ = .19 x 10⁴

r = .66 x 10

= 6.60 m .

Diameter = 13.2 m

b )

centripetal acceleration of a point on its rim = ω² r

= 9.734² x 6.6

= 625.35 m /s²

5 0
3 years ago
7. A bicycle accelerates at 2.0 m/s2. If the mass of the bicycle and rider together is
kkurt [141]

Answer:

170 N

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Since Force F = ma were m = mass = 85 kg and a = acceleration = 2.0 m/s².

So the net force on the bicycle is

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3 years ago
A food web illustrates a snake eating a rat. What is the role of the snake in the food web? A. Decomposer B.Secondary consumer C
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Primary Consumer or C.
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