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prohojiy [21]
3 years ago
7

Un automóvil lleva una velocidad inicial de 20 km/h al norte y a los 4 segundos su velocidad es de 50 km/h

Physics
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer:

Desplazamiento

Explanation:

oksian1 [2.3K]3 years ago
6 0
La unidad de aceleración es en metros por segundo al cuadrado m/s2.

Asi que, primero convertí los km/h a m/s:

50 km/h = 13.889 m/s
20 km/h = 5.556 m/s

Y los sustituís en la fórmula de aceleración:

(a = Δv / Δt). En la misma, “a” es la aceleración, “Av” es la variación de la velocidad y “At” es el tiempo que hay en esa variación.

a = (13.889 - 5.556) / 4 segs
a = 8.333 / 4
a = 2.08325 m/s2

Espero te funcione!

Marca mi respuesta como brainliest porfa!!!

Suerte :)
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noname [10]

The first part of the microscope that should first be used to adjust the focus when starting with the lowest power lens would be the coarse adjustment knob.

There are two knobs in a typical light microscope with which objects on slides can be brought into focus:

  1. Coarse adjustment knob
  2. Fine adjustment knob

The 2 knobs are used to adjust the stage to either bring it up towards the objective lens or down away from them. The coarse adjustment knob, however, moves the stage a considerable distance with each turn. The fine adjustment knob, on the other hand, only moves the stage very little with each turn.

The lowest power lenses are often short. Hence, using the coarse adjustment knob is ideal in order to quickly bring objects on slides into focus.

The fine adjustment knob comes highly recommended at high objectives because high objectives lenses are usually long and using the coarse adjustment knob can lead to a breakage of the slide by the lens.

More on bringing objects into focus on a microscope can be found here: brainly.com/question/24319677

7 0
3 years ago
Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.
horrorfan [7]

1) B) 500 J

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W=Fd=(100 N)(5 m)=500 J

2) B)  Tommy had a positive acceleration between noon and 12:30 pm.

In fact, Tommy's velocity increases between noon and 12.30 pm (at noon, he travels at 4 mph, while at 12.30 pm he travels at 6 pm). Since acceleration is equal to the rate of chang in velocity, an increase in velocity means a positive acceleration.

3) C)  The gravitational forces of people is so small it is overshadowed by that of Earth

The magnitude of the gravitational force is given by:

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the two objects. From this formula we can understand that the gravitational force exerted by a man on another man is negligible compared to the gravitational force exerted by the Earth on a man, since the Earth's mass is much greater than the mass of a man.

4) C)  Wrestler C

The force due to gravity is equal to the weight of the wrestler: W=mg, where m is the mass of the wrestler and g is the acceleration due to gravity. Since wrestler C has the greatest mass (171 pounds), it has the largest weight, so it experiences the largest force due to gravity.

5) the graph here is missing.

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7) C)  Carrie is, because velocity includes speed plus direction, and both changed.

An object is accelerating when its velocity changes. But velocity includes both speed and direction: therefore, an object is accelerating when either its speed or its direction is changing. In this example, we are told that Carrie and Sam go up and down in the carousel, therefore their velocity is changing direction, so they are accelerating for sure.

8) C)  Chemical energy changes to mechanical energy.

The energy of the battery is chemical energy, and this is converted into kinetic energy (due to the motion of the fan), which is mechanical energy.

9) A)  Their displacement is the same, zero miles

Displacement is equal to the difference between the final position and the initial position. Since the mile consists of 4 entire laps, it means that the two guys will return at their starting point at the end of the mile: therefore, their displacement is zero.

10) A)  Use an inclined plane of length 8 m.

If we want to use the same effort, we must keep the proportions of the inclined plane the same as in the first example. In the first example, the ratio between the length of the incline and its height is 4:1, and since in the second example the height is increased to 2 m, to keep the same proportions the new ratio should be 8:2, so the length of the inclined plane must be 2 m.

6 0
3 years ago
Read 2 more answers
A boat heads directly across a river. Its speed relative to the water is 2.6 m/s. It takes it 355 seconds to cross, but it ends
Zigmanuir [339]

Answer:

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

Explanation:

The relative speed of the boat to the bank Vr is the resultant of speed of boat relative to the water Vb and the speed of boat as a result of the water current or wind Vw

Vr = √(Vb^2 + Vw^2) .....1

Given;

Vb = 2.6m/s

Vw = distance downstream/time = 690m/355s

Vw = 1.94m/s

From equation 1 above; substituting the values

Vr = √(2.6^2 + 1.94^2)

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

7 0
3 years ago
Predict the speed of a car after 10.0 s when the car’s speed follows
andreev551 [17]

Answer:

48 m/s

Explanation:

The time is 10 seconds

The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows

= 4.8 × 10

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Hence the speed is 48 m/s

7 0
4 years ago
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
2 years ago
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