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prohojiy [21]
3 years ago
7

Un automóvil lleva una velocidad inicial de 20 km/h al norte y a los 4 segundos su velocidad es de 50 km/h

Physics
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer:

Desplazamiento

Explanation:

oksian1 [2.3K]3 years ago
6 0
La unidad de aceleración es en metros por segundo al cuadrado m/s2.

Asi que, primero convertí los km/h a m/s:

50 km/h = 13.889 m/s
20 km/h = 5.556 m/s

Y los sustituís en la fórmula de aceleración:

(a = Δv / Δt). En la misma, “a” es la aceleración, “Av” es la variación de la velocidad y “At” es el tiempo que hay en esa variación.

a = (13.889 - 5.556) / 4 segs
a = 8.333 / 4
a = 2.08325 m/s2

Espero te funcione!

Marca mi respuesta como brainliest porfa!!!

Suerte :)
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To what volume will a sample of gas expand if it is heated from 50.0°c and 2.33 l to 500.0°c?
Lena [83]

The volume of the gas at 500^{\circ} \text{C} is \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Further Explanation:

Consider the pressure of the gas to be constant.  

The change in the volume of the gas when the temperature of the gas is varied by keeping the pressure of the gas at a constant value is defined by the Charles' Law.

Concept:

According to the Charles law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

The Charles' law can be stated as:

\fbox{\begin\\V\propto T\\\end{minispace}}

The above expression can we written as.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

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T=273+T^\circ\text{C}}}

Here, T is the temperature in kelvin and T^\circ\text{C}}} is the temperature in centigrade.  

The initial temperature of the gas is 50^\circ\text{C}. The temperature of the gas in kelvin is.  

\begin{aligned}{T_1}&=273+50\\&=323\,{\text{K}}\\\end{aligned}

The final temperature of the gas is 500^\circ\text{C} . The temperature in kelvin is.  

\begin{aligned}{T_2}&=273+500\\&=773\,{\text{K}}\\\end{aligned}

Substitute the values of temperature and volume in the expression of the Charles' Law.  

\begin{aligned}{V_2}&=\frac{{{T_2}}}{{{T_1}}}{V_1}\\&=\frac{{773\,{\text{K}}}}{{323\,{\text{K}}}}\left({2.33\,{\text{L}}}\right)\\&=5.576\,{\text{L}}\\\end{aligned}

Thus, the volume of the gas at 500^\circ\text{C}} will be \fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}.

Learn More:  

1. Examples of wind and solar energy brainly.com/question/1062501

2. Stress developed in a wire brainly.com/question/12985068

Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Gas law  

Keywords:  

Charles law, temperature, volume, initial, final, kelvin, centigrade, 50 C, 500 degree, 500 C, 50 degree, 2,33 L, gas expand, sample, heated.

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