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prisoha [69]
3 years ago
5

In a lab, a 0.025 kg cork attached to a string is swung around in a horizontal circle. The time it takes for the cork to complet

e one revolution is timed. If the radius of the circle is 0.30 m and one revolution takes 1.25 s, find the speed of the cork and the centripetal force applied to it
Physics
1 answer:
castortr0y [4]3 years ago
7 0

Answer:

v=1.5081 m/s

F_c=0,189\ Nw

Explanation:

<u>Uniform Circular Motion </u>

The cork is performing a circular motion which we assume to be uniform (constant angular speed or angular acceleration zero)

The centripetal force applied to it is given by

F_c=m\ a_c

where m is the mass and a_c is the centripetal acceleration. This acceleration appears since the tangent speed is constantly changing direction. If w is the angular speed and r is the radius of rotation

a_c=w^2r

The speed of the cork can be found with the formula

v=wr

We can compute w since we know the rotation period <em>T=1.25 sec </em>

w=\frac{2\pi}{T}=\frac{2\pi}{1.25}=5.027\ rad/sec

Now, since r=0.30 m, let's compute v

v=wr=(5.027)(0.3)=1.5081\ m/s

a_c=5.027^2(0.3)=7.58\ m/sec^2

And finally

F_c=(0.025)\ (7.58)=0,189\ Nw

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