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Afina-wow [57]
1 year ago
5

Velocity vector and acceleration vector in a uniform circular motion are related as.

Physics
1 answer:
mr_godi [17]1 year ago
8 0

They are related as \bold{\underline {v}\,.\,\underline a }= \bold{0}

  • In a uniform circular motion, the magnitude of the speed does not change during the travel and only the instantaneous direction changes.
  • This speed is always directed along the tangent to the circle at a given point. (refer to the figure attached)
  • For any circular motion, the must-have acceleration is the centripetal acceleration that is directed towards the centre of the circular locus (if the motion has a tangential acceleration, it has a tangential acceleration additionally).
  • Therefore, both the directions of the tangential speed and the centripetal acceleration are orthogonal to each other (perpendicular: one is 90 degrees apart from the other).
  • In mathematics, 2 vectors (\underline p , \underline q) that are perpendicular to each other have a quality that their dot product (\underline p\,.\, \underline q) equal to zero vector (\bold 0) which is written as \undeline p\,.\, \underline q = \bold 0.
  • This quality can be considered when dealing with the velocity vector and the acceleration vector in a manner \underline v\,.\, \underline a =\bold 0.

#SPJ4

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An object with a mass of 78 kg is lifted through a height of 6 meters how much work is done
il63 [147K]
We got the following:
m = 78kg
h = 6m
g = 9.8 m/sec^{2} ≈ 10 m/sec^{2}
----------------------------------------------------------------------------
A = ?

As we know A = Ep = mgh    ->      potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule


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3 years ago
What is the direction of the tangential speed when a car is driving around a circular curve?
pantera1 [17]
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In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
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Answer:

Explanation:

Let the required velocity of rocket be v .

We shall use the formula of time dilation to find the velocity of rocket .

t = \frac{t'}{\sqrt{1-\frac{v^2}{c^2} } }

t = 430

t' = 38

430=\frac{38}{\sqrt{1-\frac{v^2}{c^2} } }

\sqrt{1-\frac{v^2}{c^2} } }=\frac{38}{430}

1-\frac{v^2}{c^2} = .0078

\frac{v^2}{c^2} =.9922

\frac{v}{c} = .996

v  = .996 x 3 x 10⁸ m /s

= 2.988 x 10⁸ m /s

B )

Kinetic energy of rocket

= 1/2 m v²

= .5 x 20000 x (2.988 x 10⁸ )²

= 8.9 x 10²⁰ J .

C )

This energy is 8.9 times the energy requirement of United states in the year 2005 .

7 0
3 years ago
Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates fo
eduard

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at   ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at  

using equation (1):

<u>Vf₂ = 2 Vf₁</u>

<u>It shows that final speed of Joe is twice the final speed of Jim.</u>

3 0
3 years ago
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