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Daniel [21]
2 years ago
15

When a certain powder is mixed into a solution of silver nitrate, a white precipitate forms. When the powder is added to a solut

ion of sodium hydroxide, bubbles form, which produce a noxious odor. These bubbles, when bubbled into a solution of nickel (II) hydroxide, produce a drastic color change from green to dark blue. What is the identity of this powder?
Chemistry
1 answer:
atroni [7]2 years ago
5 0

Answer:

Ammonium chloride

Explanation:

The powder is:- Ammonium chloride

When mixed with silver nitrate, white prescipitate of silver chloride is formed as:-

NH_4Cl+AgNO_3\rightarrow NH_4NO_3+AgCl

When mixed with sodium hydroxide, ammonia gas is formed which has noxious order.

NH_4Cl +NaOH\rightarrow NH_3 + H_2O + NaCl

Ammonia gas on reaction with nickel (II) hydroxide forms deep blue colored complex as shown below:-

Ni(OH)_2(s) + 6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}(aq) + 2OH^{-}(aq)

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2,7 m

Explanation:

You can solve this doing an energy balance:

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6 0
3 years ago
Read 2 more answers
Identify the types of information that are necessary to communicate with emergency responders. Select one or more: Any chemicals
oksano4ka [1.4K]

Answer:

How the incident happened

Any chemicals involved in an incident

Any other hazards present in the lab

Explanation:

Above are the types of information that are necessary to communicate with emergency responders. The emergency responders ask the first question that how the incident happened. After that they ask that is there any harmful chemicals are present in the laboratory or what types of chemicals present in the laboratory. These questions were asked by the emergency responders in order to give the patient a suitable treatment.

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2 years ago
3. Calculate the percent yield of silver chromate if 0.455 grams of silver chromate are produced
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The answer is in the photo.

8 0
3 years ago
What is the mass of 1.58 moles of CH4
HACTEHA [7]
<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})
  2. Multiply/Divide:                 \displaystyle 25.359 \ g \ CH_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0
3 years ago
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