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3 years ago

In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), how many electrons are transferred?

Chemistry

1 answer:

lora16 [44]3 years ago

7 0

C. 2

2H_2O + 2e^(-) → H_2 + 2OH^(-)

2Cl^(-) → Cl_2 + 2e^(-)

2H_2O +Cl^(-) + 2e^(-) → H_2 + Cl_2 + 2OH^(-) + 2e^(-)

2H_2O +2Cl^(-) → H_2 + Cl_2 + 2OH^(-)

This is a redox reaction in which two chloride ions transfer two electrons to two molecules of water.

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2 years ago

DIA [1.3K]

V_1=49.8mL
T_1=18°C=291K
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Using Charles law

$\\ \sf\longmapsto V_1T_2=V_2T_1$

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2 years ago

How many moles of oxygen must be placed

umka21 [38]

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:

$PV = nRT$

where:

P - pressure (in atm)

V - volume (in L)

n - amount of gas (in moles)

R - universal gas constant $0.08206 \frac{L-atm}{mol-K}$

T - temperature (in K)

In the problem, we are given the values:

P = 2.00 atm (3 significant figures)

V = 3.00 L (3 significant figures)

n = ?

T = 25.0 degrees Celsius (3 significant figures)

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:

$Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15$

Therefore, for this problem,

$Temperature\ in \ K = 25.0 +273.15\\Temperature\ in \ K = 298.15$

Solving for n using the Ideal Gas Equation:

$n \ = \frac{PV}{RT}\\n \ = \frac{(2.00 \ atm) \ (3.00 \ L)}{(0.08206 \ \frac{L-atm}{mol-K})( 298.15 \ K)} \\n \ = 0.245 \ mol$

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures.