Answer: I dont see the option choices 
Explanation:
 
        
             
        
        
        
Answer:
False 
Explanation:
Please see the attached file
 
        
                    
             
        
        
        
Answer:
B meet A 0.01 km east of flagpole
Explanation:
given data 
distance A = 5.7 km  west
velocity V1 = 8.9 km/h
distance B = 4.5 km  east
velocity V2 = 7 km/h
to find out
How far runners from the flagpole, when paths cross
solution
we know A and B are 5.7 + 4.5 = 10.2 km apart 
and we consider here B will run distance x km for meet
so time will be for B is 
time B = distance / velocity
time B = x / 7     ...................1
and 
for A distance for meet = ( 10.2 - x ) km
so time A = distance / velocity
time A = ( 10.2 - x )  / 8.9      .............2
now equating equation 1 and 2 
time A = time B 
x / 7  =   ( 10.2 - x )  / 8.9
x = 4.490 
so distance of B run for meet is 4.490 km
so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km
so B meet A 0.01 km east of flagpole
 
        
             
        
        
        
<h3><u>Answer;</u></h3>
electric potential
<h3><u>Explanation;</u></h3>
Electric potential is the electric potential energy per unit charge.
Mathematically; V =PE/q
Where; PE is the electric potential energy, V is the electric potential and q is the charge.
Electric potential is more commonly known as voltage.  If you know the potential at a point, and you then place a charge at that point, the potential energy associated with that charge in that potential is simply the charge multiplied by the potential.
 
        
        
        
Answer:
     E = -4000 N / C
Explanation:
The potential and electric field are related
          V = - E s
           E = - V / s
we reduce the magnitudes to the SI system
           s = 4 mm (1 m / 1000 mm) = 0.004 m
we calculate
           E = - 16 /0.004
           E = -4000 N / C