Given Information:
Power of bulb = w = 25 W
atts
distance = d = 9.5 cm = 0.095 m
Required Information:
Radiation Pressure = ?
Answer:
Radiation Pressure =7.34x10⁻⁷ N/m²
Explanation:
We know that radiation pressure is given by
P = I/c
Where I is the intensity of radiation and is given by
I = w/4πd²
Where w is the power of the bulb in watts and d is the distance from the center of the bulb.
So the radiation pressure becomes
P = w/c4πd²
Where c = 3x10⁸ m/s is the speed of light
P = 25/(3x10⁸*4*π*0.095²)
P = 7.34x10⁻⁷ N/m²
Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²
The correct answer would be A "<span>A light-year is the distance light travels in a year.
This is considered a unit of distance connected to the distance that light can travel in one year. It is proved that light travels at 300,000 km per second so, in 1 year, it might travel 10 trillion km.
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Answer:
Options A and D
Explanation:
In this question the student needs to collect these measurements in order to approximate the work done
A. The mass of the student
D. The final vertical height above the initial vertical position.
Workdone = mgh
m = mass
g = gravity = 9.8m/s²
h = vertical height between the initial and the final positions.
The vertical height has to be known as gravity only acts straight down.
We add the values on each of the riders:
300 + 20 + 8
= 328 grams
The LC circuit will also need a capacitance of 1.01 μF.
<h3>
What is capacitance?</h3>
Capacitance is the ratio of the amount of electric charge stored on a conductor to a difference in electric potential.
<h3>Capacitance needed for the resonance circuit</h3>
Xl = Xc
where;
- Xl is the inductive reactance
Xl = ωL
Xc = 1/ωC
ωL = 1/ωC
ω²LC = 1
C = 1/(ω²L)
C = 1/(2πf)²(L)
C = 1/(4π²f² L)
C = 1/(4π² x 100² x 2.5)
C = 1.01 x 10⁻⁶ F
C = 1.01 μF
Thus, the LC circuit will also need a capacitance of 1.01 μF.
Learn more about capacitance here: brainly.com/question/13578522
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