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1 year ago

How have the hubble and chandra telescope helped scientists find out more about these telescopes

1 answer:

6 0

Hubble has aided scientists in their understanding of the solar system. Comets and planets are observed by the telescope.

Galaxies that were there when the cosmos was still only 600 million years old have been surveyed by Hubble. Galaxies were thought to have formed when the cosmos had existed for at least the two billion years. The photos from the equipment have aided research into the evolution of galaxies.

Even previously unseen moons surrounding Pluto were found by Hubble. Scientists' understanding of how planets as well as galaxies form has been aided by the telescope.

Therefore, Hubble has aided scientists in their understanding of the solar system. Comets and planets are observed by the telescope.

To know more about Hubble

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Define: 1. acids, 2. strong acids, 3. weak acids.

Reika [66]

H^+ = acid
OH^- = alkaline

Acids have a pH of below 7. The lower the number, the strongest the acid.

4 0

3 years ago

Read 2 more answers

(PLZ ANSWER SOON)

almond37 [142]

Answer:

10.5 k.J.

Explanation:

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3 years ago

MyRoad is a(n):

Assoli18 [71]

c. online college and career planning resource you can access once you take the PSAT.

Explanation:

MyRoad is an online platform where college and career planning resources can be accessed when the PSAT has been taken.

It provides an online mentor-ship and guidance for approaching the more robust college life.

The platform allows diverse students to access useful information about their intended colleges.

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3 years ago

Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.

hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

Number of moles of gas = 2.00 mol

Temperature = 36°C (36+273= 309K)

Pressure of gas = 1120 torr

Solution:

Formula:

PV = nRT

V = nRT/P

V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr

V = 38563.2 torr • L / 1120 torr

V = 34.43 L

L to mL

34.43 L ×1000 mL / 1 L

34430 mL

5 0

3 years ago

Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc

Ber [7]

Answer:

The balanced equation for this reaction will be

$CH4 + 4F2$ → $CF4 + 4HF$

We can see that 1 mole of methane requires 4 moles of fluorine but we have 0.41 moles of CH4 and 0.56mole of F2

So using the unitary method we will get that

1 mole of CH4 → 4 mole of 4 mole of fluorine

0.41 mole of methane → 4*0.41 = 1.64 mole of fluorine for complete reaction

but we have only 0.56 mole of fluorine that means fluorine is the limiting reagent and the product will only be formed by only this amount of fluorine.

4 moles of fluorine → 1 mole of CF4

0.56 mole → $\frac{1}{4} * 0.56$ = 0.14mole of CF4

4 moles of fluorine → 4 moles of HF

0.56 mole of fluorine → 0.56 mole of HF

now to find the heat released we have the formula as

DELTA H = n * Delta H of product - n *delta H of reactant

where n is the moles of the reactant and product.

note: since no information is given about the enthalpies of the species we leave it on general equation also you need to add the product side enthalpy of the species present and similarly on the product side.

8 0

3 years ago