Answer:
The structural level of a protein least affected by a disruption in hydrogen bonding is the primary level.
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.
HNO2 <-> H(+) + NO2(-)
Next, create an ICE table
HNO2 <--> H+ NO2-
[]i 0.230M 0M 0M
Δ[] -x +x +x
[]f 0.230-x x x
Then, using the concentration equation, you get
4.5x10^-4 = [H+][NO2-]/[HNO2]
4.5x10^-4 = x*x / .230 - x
However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable,
assume 0.230-x ≈ 0.230
4.5x10^-4 = x^2/0.230
Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.
We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.
Then to find percent dissociation, you do final concentration/initial concentration.
0.01M/0.230M = .0434 or
≈4.34% dissociation.
Answer:
A) 0.50 M
Explanation:
The computation of the number of molarity of the NaOH is given below:
As we know that
Molarity = Moles ÷ liters
where
Moles is 20
And, the liters is 40
So, the molarity is
= 20 ÷ 40
= 0.50 M
hence, the molarity of the NaOH solution is 0.50 M
Therefore the A option is correct
