Answer:
CH2O
Explanation:
Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.
C = 5.692/14.229 * 100 = 40%
O = 7.582/14.229 * 100 = 53.29%
H = 0.955/14.229 * 100 = 6.71%
We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.
C = 40/12 = 3.333
O = 53.29/16 = 3.33
H = 6.71/2 = 6.71
Dividing by the smaller value which is 3.33
C = 3.33/3.33 = 1
O = 3.33/3.33= 1
H = 6.71/3.33 = 2
The empirical formula of the compound ribose is CH2O
In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
Answer:
Weathering and erosion
Explanation:
Weathering can be explained as the breaking down of rocks/minerals on the surface of the Earth as a result of contact with biological organism, water, air and other factors
. There are 3 common types of weathering which are;
1) physical weathering
2) biological weathering
3) chemical weathering
Erosion can be regarded as a geological process, whereby earthen material are been transported away by natural forces, these forces could be wind as well as water.
Therefore, as you were climbing a a mountain, you noticed that rocks were crumbling below your feet and moving down the mountain. What is observed are weathering and erosion processes.
After the weakening and broken up of the rock by weathering then erosion transport the bit of the rock down the mountain as you are climbing, which means the "weathering process" breakdown and the "erosion process" involves the transport or movement of the bit of the rocks
Answer:
Concentration of nitrate in the new solution = 0.007 M
Explanation:
Given:
Concentration nitrate solution = 0.070 m
Volume of aliquote of the nitrate solution is add = 10.0 ml
Total volume = 100 ml
Find:
Concentration of nitrate in the new solution
Computation:
Number of M. mole = 0.070 m x 10.0 ml
Number of M. mole = 0.7 m-moles
Concentration of nitrate in the new solution = 0.7 m-moles / 100 ml
Concentration of nitrate in the new solution = 0.007 M
Answer:
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