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2 years ago

What is the binding energy of a mole of nuclei with a mass defect of 0.00084 kg/mol?

Chemistry

1 answer:

lana [24]2 years ago

7 0

Answer:

7.56 x 10^13 J/mol

Explanation:

Binding energy = (Mass defect) × (velocity of light)² = (84 × 10^-5) × (3 × 10^8)^2 = 756 × 10^11 J = 7.56 × 10^13 J/mol

Hope this helps -Paige

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How much heat is required to decompose 25.5 grams of NaHCO3? 2NaHCO3(s) + 129 kJ 2Na2CO3(s) + H2O(

Vaselesa [24]

To determine the heat required in order to decompose a certain amount of a substance, we need information on the heat needed to decompose one mole of the substance. This value are readily available online and other sources. For this reaction, the heat needed is 129 kJ per 2 mol of NaHCO3. We calculate as follows:

129 KJ / 2 mol NaHCO3 (1 mol / 84.01 g ) (25.5 g NaHCO3 ) = 19.58 kJ of heat is needed.

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3 years ago

Please Help, I did it but I want to make sure, 100 points

Daniel [21]

Answer:

Acid - A compound that increases hydrogen ions (H+) when it is dissolved in a solution

pH - A value from 0 to 14 that is used to specify how acidic or basic a compound is when it is dissolved in water

Base - A compound that increases hydroxide ions (OH−) when it is dissolved in a solution

Litmus paper - Used to measure the pH of substances by determining their hydrogen ion concentration

8 0

3 years ago

Read 2 more answers

25 g of a compound is added to 500 mL of water if the freezing point of the resulting solution is

vlabodo [156]

Answer:

a) 119 g/mol

Explanation:

-We apply the formula for freezing point depression to obtain the molality of the solution:

$\bigtriangleup T_f=K_fm, \ \ K_f=1.36\textdegree C/m\\\\\therefore m=\frac{\bigtriangleup T_f}{K_f}\\\\=\frac{0.57\textdegree C}{1.36\textdegree C}\\\\=0.4191\ mol/Kg\\\\$

#We use the molality above to calculate the molar mass:

$m=\frac{0.4191\ mol}{1\ Kg}=\frac{25\ g}{0.5\ Kg}\\\\\therefore 1 \ mol=\frac{25\ g}{0.5\ Kg}\times\frac{1\ Kg}{ 0.4191}\\\\=119.3033\approx 119\ g/mol$

Hence, the molar mass of the compound is 119 g/mol

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3 years ago

What is A collection of waves called

sattari [20]

When waves act together, you talk about "interference". When they reinforce each other, it is "constructive interference". When they cancel each other, it is "destructive interference".

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3 years ago

Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o

Pani-rosa [81]

Answer:

1) 0,081 ft/s

2) 0,746 lb/s

Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

where:

Q, flow [ft3/s]
A, cross section of the pipe [ft2]
v, velocity of the fluid [ft/s]

To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

$Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}$

As the pipe has a circular section, we use A=πd^2/4:

$d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\ A=\pi \frac{0,355^{2} }{4}=0,0989ft2$

Finally:

Q=vA......................v=Q/A

$v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s$

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW

where:

SG = specific gravity,

ρ = density of the material [lb/ft3]

ρW = density of water [lb/ft3] = 62.4 lbs/ft3

then:

ρ = SG*ρW = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

$0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s$

7 0

3 years ago