Question

The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is _________

Answer 1

Answer:

$2HNO_3(aq)+Sr(OH)_2(aq)\rightarrow Sr(NO_3)_2(aq)+2H_2O(l)$

Explanation:

Hello,

In this case, since nitric acid is HNO₃ and strontium hydroxide is Sr(OH)₂ we can represent the balanced chemical reaction by equaling the atoms of strontium, nitrogen, oxygen and hydrogen at both reactants and products as shown below:

$2HNO_3(aq)+Sr(OH)_2(aq)\rightarrow Sr(NO_3)_2(aq)+2H_2O(l)$

Best regards.

Answer 2

Answer:

The balanced reaction between aqueous nitric acid and aqueous strontium hydroxide is  Sr(OH)₂ + 2 HNO₃ → Sr(NO₃)₂ + 2 H₂O

Explanation:

A neutralization reaction is one in which an acid (or an acid oxide) reacts with a base (or basic oxide) and the products of which are salt and water.

The general formula for this type of reaction is:

Acid + Base → Salt + Water

In this case, the neutralization reaction that occurs is:

Sr(OH)₂ + HNO₃ → Sr(NO₃)₂ +  H₂O

The Law of Conservation of Matter, also called the Law of Conservation of Mass or the Lomonosov-Lavoisier Law, postulates that "mass is neither created nor destroyed, it is only transformed". This means that the reagents interact with each other and form new products with different physical and chemical properties than the reagents because the atoms of the substances are arranged differently.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

Left side: 1 nitrogen, 3 hydrogen, 5 oxygen and 1 strontium

Right side: 2 nitrogen, 2 hydrogen, 7 oxygen and 1 strontium

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  

In general, hydrogen and oxygen balance in the end. So, starting to balance nitrogen N:

Sr(OH)₂ + 2 HNO₃ → Sr(NO₃)₂ +  H₂O

Then:

Left side: 2 nitrogen, 4 hydrogen, 8 oxygen and 1 strontium

Right side: 2 nitrogen, 2 hydrogen, 7 oxygen and 1 strontium

Now, with the nitrogen and strontium being balanced, it is time to balance the hydrogen, obtaining:

Sr(OH)₂ + 2 HNO₃ → Sr(NO₃)₂ + 2 H₂O

Then:

Left side: 2 nitrogen, 4 hydrogen, 8 oxygen and 1 strontium

Right side: 2 nitrogen, 4 hydrogen, 8 oxygen and 1 strontium

Since you have the same amount of each compound on each side of the reaction, the reaction is balanced.