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blondinia [14]
3 years ago
7

Two friends, Burt and Ernie, are standing at opposite ends of a uniform log that is floating in a lake. The log is 3.2m long and

has mass 290kg . Burt has mass 33kg and Ernie has mass 32kg, Initially the log and the two friends are at rest relative to the shore. Burt then offers Ernie a cookie, and Ernie walks to Burt's end of the log to get it,then Relative to the shore, what distance has the log moved by the time Ernie reaches Burt? Neglect any horizontal force that the water exerts on the log and assume that neither Burt nor Ernie falls off the log.
Physics
1 answer:
Svetach [21]3 years ago
8 0

Answer:

x = 0.29 m

Explanation:

As we know that the net external force on the system of mass is ZERO

so here the COM of whole system will always remain at rest

So we will have

m_1\Delta x_1 + m_2\Delta x_2 + m_3\Delta x_3 = 0

here we know that Ernie walks to Burt's position so we have

33 x + 290 x + 32(-3.2 + x) = 0

355 x = 102.4

so we have

x = \frac{102.4}{355}

x = 0.29 m

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A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas
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<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

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In the question,

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Now,

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Splash is heard after = 2.92 s

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<u>Time taken by sound to travel the shortest distance along the hypotenuse of the triangle</u> thus formed is,

t = 2.92 - 2.747

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Speed of throwing of ball is given by,

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(b).

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Speed of sound = 331 m/s

So,

<u>Distance traveled by sound</u> is,

Distance=331\times 0.172\\Distance=56.932\,m

So,

Distance traveled in the horizontal by ball is,

Distance=\sqrt{56.932^{2}-37^{2}}\\Distance=43.269\,m

So,

Speed of the ball thrown is given by,

Speed=\frac{Distance}{Time}\\Speed=\frac{43.269}{2.747}\\Speed=15.75\,m/s

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8 0
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Kepler’s
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We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496
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Let’s work
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(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel
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1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/(
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M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The
closest answer is 1.99
× 10^30

(it may vary
a little with rounding – the difference is less than 1%)


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