1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PilotLPTM [1.2K]
4 years ago
6

(1

Physics
1 answer:
mart [117]4 years ago
7 0

Answer:

The boat should point in angle to the perpendicular to the shore is, Ф = 12° 22'

Explanation:

Given data,

The velocity of the boat, V = 8.2 m/s

The velocity of the flow of the river, V' = 1.8 m/s

Let Ф formed by the boat perpendicular to the shore,

The two velocity components along the perpendicular axes are V and V'

Therefore,

                                  tan Ф = V' / V

                                             = 1.8 / 8.2

                                             = 0.2195

Therefore,

                                         Ф  = tan⁻¹ (0.2195)

                                              = 12° 22'

Hence, the boat should point in angle to the perpendicular to the shore is, Ф = 12° 22'

You might be interested in
Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5  = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0
4 years ago
What is a substance that when mixed with water turns blue litmus paper red
alekssr [168]
When blue litmus paper is dipped in acid the paper turns red.

hope this helps :)


5 0
4 years ago
A forklift lifts 5 boxes from the ground to a height of 2 meters (m). The boxes push down with a force of 1000 newtons (N). How
Nata [24]
Hello!

Answer:

2000 J

Explanation

Work equation is expressed as:

W=F.d.Cos \alpha

Where:

F: Applied force
d: traveled distance
α: Angle between the direction of the force and the direction of the movement. (in this case, both of the direction are the same, so the angle is 0°)

By substituting:

F=1000N.2m.Cos(0)=2000N.m=2000 J

Have a nice day!
8 0
3 years ago
If the Velocity of the body<br> is increased to 3v, determine the kinetic energy
Rom4ik [11]

ANSWER; KE=5mv^2 so it is proportional to v^2.

Explanation:So if you triple the velocity you are replacing v with 3v. Then you get (3v)^2=9v^2.

7 0
3 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
Other questions:
  • G (where g=9.8 m/s2). If an object’s mass is m=10. kg, what is its weight?
    8·1 answer
  • Choose one of the six fitness related components that are used in gymnastics.
    13·1 answer
  • A 23.3-kg mass is attached to one end of a horizontal spring, with the other end of the spring fixed to a wall. The mass is pull
    5·1 answer
  • Hydrogen is a nonmetal with many nonmetal properties. Why is it on the periodic table with the metals in Group 1?
    12·1 answer
  • For a given wing–body combination, the aerodynamic center lies 0.03 chord length ahead of the center of gravity. The moment coef
    14·1 answer
  • When very electronegative atoms, like oxygen, bond to atoms with lower electronegativity, like lithium, what's the result?
    5·1 answer
  • A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?
    12·1 answer
  • What is the relationship between kinetic and potential energy of a falling object
    7·1 answer
  • What is the magnitude of velocity for a 3,100 kg car possessing 4,100 kg•m/s of momentum?​
    10·2 answers
  • Alguien que sepa de electromecánica porfavor
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!