Answer:
225 N
Explanation:
Force = Mass . Acceleration
F = 45 . 5
F = 225 N
Answer:
1.791 MN
Explanation:
Thrust of the rocket can be found using the relation
T = v.dm/dt, where
T = thrust off the rocket
v = speed of the rocket, 9 km/s = 9000 m/s
dm/dt = rate at which fuel burns, 199 kg/s
Substituting the values into the formula, we have
T = 9000 * 199
T = 1791000 N
T = 1.791*10^6 N
Since 1 MN = 10^6, thus
T = 1.791 MN
Answer:
Yes, in case of uniform velocity
Explanation:
This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.
Since, acceleration is defined as the rate of change of velocity.
Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.
a = ΔV/t = 0/t
a = 0 m/s²
So, the acceleration of the body is 0 m/s², but it has a uniform velocity
<u>Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.</u>
Complete question
A cannon with a muzzle velocity of 500. meters per second fires a cannonball at an angle of 30.° above the horizontal. What is the vertical component of the cannonball's velocity as it leaves the cannon?
A 0.0 m/s
B 250. m/s
C 433 m/s
D 500. m/s
Answer:
The correct option is C
Explanation:
From the question we are told that
The velocity is 
The angle is 
Generally the vertical component of the canon ball is mathematically represented as
=> 
=> 
Answer:
<em> The mas unit is the the 'Kilogram' written as 'kg'</em>
<em>Volume is 10 L</em>
<em></em>
Explanation:
The complete question is
If you have a density of 100 kg/L, and a mass of 1000 units, tell me the following: First, what are the mass units?
Second, what is the volume
mass units is the 'Kilogram', written as 'kg'
density = mass/volume = 100 kg/L
the mass = 1000 kg
volume = mass/density = 1000/100 =<em> 10 L</em>
