A forklift lifts 5 boxes from the ground to a height of 2 meters (m). The boxes push down with a force of 1000 newtons (N). How
1 answer:
You might be interested in
<h2>Answer: 1.252</h2>
Explanation:
We are given this equation and we need to find the value of :
(1)
Firstly, we have to clear :
(2)
Applying<u> Natural Logarithm</u> on both sides of the equation (2):
(3)
(4)
According to the Natural Logarithm rules , so (4) can be written as:
(5)
Finally:
The speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.
<h3>Angular Speed of the pulley </h3>
The angular speed of the pulley after the block m1 fall through a distance, d, is obatined from conservation of energy and it is given as;
K.E = P.E
Substitute the given parameters and solve for the angular speed;
The linear speed of the block after travelling 0.7 m;
v = ωR₂
v = 35.39 x 0.03
v = 1.1 m/s
Thus, the speed of the block after it has moved the given distance away from the initial position is 1.1 m/s.
Learn more about conservation of energy here: brainly.com/question/24772394