Ask question

Ask question

All categories

Ira Lisetskai [31]

3 years ago

15

A large crystal of potassium manganate is placed in the bottom of a beaker of cold water, and left for several hours. Describe w

hat would be seen after 5 minutes

1 answer:

Katarina [22]3 years ago

5 0

Potassium manganate would dissolve in water

You might be interested in

If Sally has 250 grams of cement, how many kilograms does she have? How many milligrams?

MissTica

Answer:

0.250 kg

2500 g

Explanation:

1 kg = 1000g

1g = 10 mg

8 0

2 years ago

Is sugar a compound or a mixture?

puteri [66]

Answer:

compound

Explanation:

3 0

2 years ago

Read 2 more answers

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

3 years ago

What is the volume of 8.80 g of CH4 gas at STP?

Ann [662]

Answer:

12.32 L.

Explanation:

The following data were obtained from the question:

Mass of CH4 = 8.80 g

Volume of CH4 =?

Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:

Mass of CH4 = 8.80 g

Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol

Mole of CH4 =?

Mole = mass/Molar mass

Mole of CH4 = 8.80 / 16

Mole of CH4 = 0.55 mole.

Finally, we shall determine the volume of the gas at stp as illustrated below:

1 mole of a gas occupies 22.4 L at stp.

Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.

Thus, 8.80 g of CH4 occupies 12.32 L at STP.

6 0

3 years ago

Rubbing alcohol evaporates from your hand quickly, leaving a cooling effect on your skin. Because evaporation is an example of a

Ludmilka [50]

The molecules in gas are farther apart and have more room to bounce around than liquid

3 0

3 years ago

Read 2 more answers