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Feliz [49]
3 years ago
8

Compare the dipole moments of the following pairs of molecules and determine whether the first is "Greater Than", "Less Than" or

"Equal to" the second.
O The dipole moment of ClO2 is _____ the dipole moment of SO2
O The dipole moment of SiF4 is _____ the dipole moment of SF4
O Dipole moment of SO2 is ______the dipole moment of SO3
O The dipole moment of BeCl2 is _____ the dipole moment of SCl2
O The dipole moment of H2O is ______ the dipole moment of H2S
Chemistry
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

Greater than

Less than

Greater than

Less than

Greater than

Explanation:

The dipole moment is the difference of electronegativity between the atoms in a molecule, and the total is the sum of the dipole moments of the bonds. So, it depends on the geometry of the molecule. When the dipole moment is 0 the molecule is nonpolar, when it is different from 0 the molecule is polar.

Both ClO₂ and SO₂ have angular geometry because there are lone pairs of electrons in the central atom (Cl and S), but Cl has a higher value of electronegativity than S, so the dipole moment must be greater.

SiF₄ is a nonpolar molecule, which has tetrahedral geometry and no lone pairs at the central atom. SF₄ has lone pairs at the central atom, and then the molecule is polar, so the dipole moment of SiF₄ is less than of SF₄.

The SO₃ molecule has no lone pairs at the central atom and has trigonal geometry, so it's a nonpolar molecule. SO₂ has angular geometry and it's a polar molecule, so the dipole moment of SO₂ is greater.

BeCl₂ has a linear geometry and is a nonpolar molecule. SCl₂ has an angular geometry, and it's a polar molecule, so the dipole moment of BeCl₂ is less than the dipole moment of SCl₂.

Oxygen has a higher electronegativity than the sulfur, and both molecules are polar with angular geometry, so the dipole moment of H₂O is greater.

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All solutions<br>are mixtures; but<br>all mixtures are<br>not solutions.<br>why?​
aleksklad [387]

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5 0
3 years ago
What is the % composition of Carbon in Chromium (iii) Carbonate
photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

\begin{gathered} C\rightarrow3\times12=36 \\  \\ O\rightarrow9\times16=144 \\  \\ Cr\rightarrow2\times52=104 \end{gathered}

The molar mass will be thus:

M=36+104+144=284\text{ g/mol}

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\  \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}

The percent composition of Carbon is thus 12.7 %.

8 0
1 year ago
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