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Feliz [49]
3 years ago
8

Compare the dipole moments of the following pairs of molecules and determine whether the first is "Greater Than", "Less Than" or

"Equal to" the second.
O The dipole moment of ClO2 is _____ the dipole moment of SO2
O The dipole moment of SiF4 is _____ the dipole moment of SF4
O Dipole moment of SO2 is ______the dipole moment of SO3
O The dipole moment of BeCl2 is _____ the dipole moment of SCl2
O The dipole moment of H2O is ______ the dipole moment of H2S
Chemistry
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

Greater than

Less than

Greater than

Less than

Greater than

Explanation:

The dipole moment is the difference of electronegativity between the atoms in a molecule, and the total is the sum of the dipole moments of the bonds. So, it depends on the geometry of the molecule. When the dipole moment is 0 the molecule is nonpolar, when it is different from 0 the molecule is polar.

Both ClO₂ and SO₂ have angular geometry because there are lone pairs of electrons in the central atom (Cl and S), but Cl has a higher value of electronegativity than S, so the dipole moment must be greater.

SiF₄ is a nonpolar molecule, which has tetrahedral geometry and no lone pairs at the central atom. SF₄ has lone pairs at the central atom, and then the molecule is polar, so the dipole moment of SiF₄ is less than of SF₄.

The SO₃ molecule has no lone pairs at the central atom and has trigonal geometry, so it's a nonpolar molecule. SO₂ has angular geometry and it's a polar molecule, so the dipole moment of SO₂ is greater.

BeCl₂ has a linear geometry and is a nonpolar molecule. SCl₂ has an angular geometry, and it's a polar molecule, so the dipole moment of BeCl₂ is less than the dipole moment of SCl₂.

Oxygen has a higher electronegativity than the sulfur, and both molecules are polar with angular geometry, so the dipole moment of H₂O is greater.

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How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant
nika2105 [10]
<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 0.025305 \ mol \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0
2 years ago
How many grams of MgCl2 (molar mass = 95.20 g/mol) will be formed from 25.6 mL of a 0.100 M HCL solution reacting with excess ma
lorasvet [3.4K]
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of HCl to MgCl₂ is 2:1
we have been told that Mg is in excess therefore HCl is the limiting reactant 
number of HCl moles reacted - 0.100 mol/L x 0.0256 L = 0.00256 mol
according to molar ratio, number of MgCl₂ moles formed - 0.00256/2 
Therefore number of MgCl₂ moles formed - 0.00128 mol
mass of MgCl formed - 0.00128 mol x 95.20 g/mol = 0.122 g
3 0
3 years ago
Read 2 more answers
Question 8 (10 points)
I am Lyosha [343]

Answer:

positively charged elctrons

4 0
3 years ago
Read 2 more answers
If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade
Gemiola [76]

Answer:

it shows the breakdown of the atom

Explanation:

it will show it molecularly

7 0
3 years ago
9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r
Mumz [18]

Answer

b. 95%

Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

Mass of K that reacted = 25.00 g

Equation: 4K(s) + O₂(g) → 2K₂0(s)

What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

From the balanced equation, 4 mol K produced 2 mol K₂O

Molar mass of K₂O = 94.20 g/mol)

Molar mass of K = 39.10 g/mol)

This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O

So 25.00 g K will produce:

\frac{25.00\text{ }g\text{ }K\times188.40\text{ }g\text{ }K₂O}{156.40\text{ }g\text{ }K}=30.1151\text{ }g\text{ }K₂O

Actual yield of K₂O = 28.56 g

Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\  \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\  \\ Percent\text{ }yield=0.9484\times100\% \\  \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}

Therefore, the percent yield for the reaction is 95%.

3 0
1 year ago
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