The first mistake was made in step 1 because they took out the x’s it should be 10x-25+2x+8=43
answer:
Step by step solution:
1) put the numbers in order:
25,25,29,31,33,37,38,42,46
2) find the median:
25,25,29,31,33,37,38,42,46
33
3) find the median of the first quartile:
25,25,29,31
25 and 29
25+29= 54
54/2
27
Q1= 27
Answer:
Step-by-step explanation:
![\sqrt[3]{54c}=\sqrt[3]{3*3*3*2c} =3\sqrt[3]{2c}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B54c%7D%3D%5Csqrt%5B3%5D%7B3%2A3%2A3%2A2c%7D%20%3D3%5Csqrt%5B3%5D%7B2c%7D)
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<h3>Final value : x² -9x - 11</h3>
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<h3>Step by step </h3>




2x + 1 = ⅕ × (x² + x - 6)
2x + 1 = ⅕x² + ⅕x - 6/5
1/5x² +1/5x - 2x - 6/5 - 1 = 0
1/5x² -9/5x - 11/5 = 0
x² - 9x - 11 = 0. #times by 5
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#Give me brainliest pls im tired typing all of this
738.
3200/4.33= 739.01
The closest to that is 738