27)
Equation of the existing water pipe's line
a) slope, m = rise / run = Δy / Δx = 3/2
b) y-intercept, b = 3
equation: y = mx + b = (3/2)x + 3
Equation of the new water pipe's line
slope, m = - 1 / (slope of the perpendicular line) = - 1 / (3/2) = - 2/3
point (0,2)
=> y - 2 = (-2/3) (x - 0) => y = (-2/3)x + 2 <---- equation of the new pipe
28)
two parallel lines have the same slope =>
slope, m = rise / run = Δy / Δx = [4 - 0] / [11 - 8] = 4 / 3
point (4,5) => y - 5 = (4/3) (x - 4)
=> y = (4/3)x - 16/3 + 5 = (4/3)x - 1/3
y = (4/3)x - 1/3 <--- equation of the new bike path
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
The range of a list of numbers is the biggest number minus the smallest number. In this case, it is $4.79-$4.09 which equals $0.70.
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Answer c venue hiddenwords was your gonna night you want
