Answer:
Precipitation
Explanation:
There are four main stages in the water cycle. They are evaporation, condensation, precipitation and collection. Let's look at each of these stages. Evaporation: This is when warmth from the sun causes water from oceans, lakes, streams, ice and soils to rise into the air and turn into water vapour (gas).
Answer:
8.87 * 10^23 molecules of Ne
Explanation:
STP means standard temperature and pressure which is 0 degree Celsius and 1 atm. There's a law that says at STP 1 mole of any gas at occupies 22.4 liters of volume. We are gonna use this to do our conversion.
33.0 L Ne * 1mol Ne/22.4L Ne = 1.47321428571 mol Ne (this is moles of Neon)
Now we know avogadro number says there's 6.022*10^23 molecules in 1 mole of anything so we use this to convert the previously calculated moles of Neon to moleculues.
1.47321428571 mol Ne * 6.022*10^23 molecules/1mol Ne = 8.87 * 10^23 molecules of Ne
Answer: Activation energy
Explanation:
In a chemical reaction, the reactants contains particles which must collide in order for a reaction to occur. The rate of reaction depends on the frequency of effective collision between the reacting particles. Effective collision are those that result in reactions, which when they occur the colliding particles become activated with increased kinetic energy.
This energy must exceed a particular energy barrier for a particular reaction if the reaction must take place. This energy barrier that must be overcome before a reaction takes place is known as the ACTIVATION ENERGY.
To explain further, when two particles or molecules A and B come in contact with each other, for a reaction to take place, they must collide with a sufficient force to break the bond that exists between them. The minimum combined kinetic energy these reactant particles must possess in order for their collision to result in a reaction is called the activation energy.
Answer:
pH = 4.164
Explanation:
The first process is to find the initial moles for the base (B) & the acid (HA)
i.e.
![= \dfrac{27 mL \times 0.0758 \ moles \ \ of \ B}{1000 \ mL}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B27%20mL%20%5Ctimes%200.0758%20%5C%20moles%20%5C%20%5C%20of%20%5C%20B%7D%7B1000%20%5C%20mL%7D)
![=0.0020466](https://tex.z-dn.net/?f=%3D0.0020466)
![\simeq 2.047\times 10^{-3} \ moles \ of \ B](https://tex.z-dn.net/?f=%5Csimeq%202.047%5Ctimes%2010%5E%7B-3%7D%20%5C%20moles%20%5C%20of%20%5C%20B)
![= \dfrac{27 mL \times 0.0553 \ moles \ \ of \ HA}{1000 \ mL}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B27%20mL%20%5Ctimes%200.0553%20%5C%20moles%20%5C%20%5C%20of%20%5C%20HA%7D%7B1000%20%5C%20mL%7D)
![=0.0014931](https://tex.z-dn.net/?f=%3D0.0014931)
![\simeq 1.493\times 10^{-3} \ moles \ of \ HA](https://tex.z-dn.net/?f=%5Csimeq%201.493%5Ctimes%2010%5E%7B-3%7D%20%5C%20moles%20%5C%20of%20%5C%20HA)
The acid with base reaction is expressed as;
HA + B → A⁻ + HB⁺
to 1.493 × 10⁻³ 2.047 × 10⁻³ - -
- 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³
0 5.54 × 10⁻⁴ 1.493 × 10⁻³ 1.493 × 10⁻³
From observation; both the acid & base weak
Given that:
The pKa for base = 4.594
The pKa for acid = 3.235
Recall that;
pKa = -log Ka
So; Ka = ![\mathbf{10^{-Ka}}](https://tex.z-dn.net/?f=%5Cmathbf%7B10%5E%7B-Ka%7D%7D)
By applying this:
For Base; Ka =
= 2.5468 × 10⁻⁵
For Acid: Ka =
= 5.821 × 10⁻⁴
After the reaction; we have the base with its conjugate acid & conjugate base of acid; Thus, since the conjugate acid of the base possesses a higher value of K, it is likely it would be the one to define the pH of the solution.
By analyzing the system, we have:
HB⁺ + H₂O ↔ B + H₃O⁺
![\dfrac{5.54\times 10^{-4}}{0.1 \ L}](https://tex.z-dn.net/?f=%5Cdfrac%7B5.54%5Ctimes%2010%5E%7B-4%7D%7D%7B0.1%20%5C%20L%7D)
to 0.01493 M 0.00554 M
- x x x
0.01493 - x 0.00554 - x x
Thus;
![2.5468 \times 10^{-5} = \dfrac{(0.00554 -x)\times x}{(0.01493-x)}](https://tex.z-dn.net/?f=2.5468%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20%5Cdfrac%7B%280.00554%20-x%29%5Ctimes%20x%7D%7B%280.01493-x%29%7D)
Using the common ion effect;
0.00554 - x
0.00554 &
0.01493 - x
0.01493
∴
![x = \dfrac{2.5468 \times 10^{-5} \times 0.01493}{0.00554}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B2.5468%20%5Ctimes%2010%5E%7B-5%7D%20%5Ctimes%200.01493%7D%7B0.00554%7D)
x = [H₃O⁺] = 6.8635 × 10⁻⁵
∴
pH = -log(6.8635 × 10⁻⁵)
pH = 4.164
Low pressure and low temperature as the lower these are, the lower the kinetic energy is.