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3 years ago

What will happen if position of an effort and load are interchanged in the hydraulic press?why?

Physics

1 answer:

denis-greek [22]3 years ago

3 0

Answer:

Will load input interchange

Explanation:

The only thing that happens is the working position and the load input will interchange with each other. If the work output requirement changes with the hydraulic-press change. None of that destroyed.

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(This is a non-relativistic warm-up problem, to get you to think about reference frames.) A girl throws a baseball upwards at ti

____ [38]

Answer:

X(t) = 9.8 *t - 4.9 * t^2

Explanation:

We set a frame of reference with origin at the hand of the girl the moment she releases the ball. We assume her hand will be in the same position when she catches it again. The positive X axis point upwards.The ball will be subject to a constant gravitational acceleration of -9.81 m/s^2.

We use the equation for position under constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a *t^2

X0 = 0 because it is at the origin of the coordinate system.

We know that at t = 2, the position will be zero.

X(2) = 0 = V0 * 2 + 1/2 * -9.81 * 2^2

0 = 2 * V0 - 4.9 * 4

2 * V0 = 19.6

V0 = 9.8 m/s

Then the position of the ball as a function of time is:

X(t) = 9.8 *t - 4.9 * t^2

5 0

2 years ago

A 4.2 kg parachutist is moving straight downward with a speed of 3.85 m/s

statuscvo [17]

Kinetic energy= .5 x m x v^2
KE=.5 x 4.2 x 3.85^2
KE=31.13

4 0

2 years ago

Brittle- would break when struck with force *<br> A-Metal<br> B-Nonmetal<br> C-Metalloid

bazaltina [42]

-B because metal hardly breaks but non metal items such as glass or plastic does!

4 0

2 years ago

Read 2 more answers

A machine carries a 100kg cargo to a boat at a rate of 10m/s2. The distance between the ground to the boat is 50ft. If the machi

klasskru [66]

Answer:

50.8 watt

Explanation:

we know that P=W÷t

W=F.S S-->distance=50 ft= 15.24 m

F=ma

=100×10=1000 N

SO W= 1000×15.24

=15240 J

NOW

P=W÷t t=5 mints = 5×60=300 sec

P=15240÷300

P=50.8 watt

8 0

3 years ago

An experiment is carried out to measure the extension of a rubber band for different loads.

PtichkaEL [24]

Complete question is;

An experiment is carried out to measure the extension of a rubber band for different loads.

The results are shown in the image attached.

What figure is missing from the table?

Answer:

17.3 cm

Explanation:

The image attached showed values for load, extension and initial length.

Now, the first length there is 15.2 cm and as such it's corresponding extension is 0 because it has no preceding measured length.

The second measured length is 16.2 cm. Since it's initial measured length is 15.2 cm, then the extension has a formula; final length - initial length.

This gives: 16.2 - 15.2 = 1 cm

This corresponds to what is given in the table.

For the next measured length, it is blank but we are given the extension to be 2.1 cm. Now, since the initial measured length is 15.2 cm.

Thus;

2.1 cm = Final length - 15.2 cm

Final length = 15.2 + 2.1

Final length = 17.3 cm

3 0

2 years ago