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SOVA2 [1]
3 years ago
8

How does the oxidation state of O change in the following reaction?

Chemistry
1 answer:
Liula [17]3 years ago
8 0

Answer:

Oxygen Doesn't change

However, Li is oxidized (0 to +1), Na is reduced (+1 to 0)

Explanation:

On reactant side, Oxygen has -2 oxidation charge because we know common oxidation states such as oxygen -2, hydrogen +1 etc.

So NaOH, O is -2, H is +1, so Na has to be +1 to equal total charge of compound

In product side, LiOH, again O has to be -2, H is +1, so Li +1 as well..

We see that oxygen oxidation state doesn't change. However, for Li it becomes oxidized going from 0 to +1 whereas, Na is reduced going from +1 to 0.

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Hurrrryyyyy pls
deff fn [24]

Answer:

The growth of the plant

Explanation:

The growth of the plant from the bean soil is the dependent variable I believe. This is because it could change depending on many factors for e.g. the amount of light or water

8 0
3 years ago
What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k valu
pantera1 [17]
<span>Answer: 8.15s
</span><span />

<span>Explanation:
</span><span />

<span>1) A first order reaction is that whose rate is proportional to the concenration of the reactant:
</span><span />

<span>r = k [N]
</span><span />

<span>r = - d[N]/dt =
</span><span />

<span>=> -d[N]/dt = k [N]
</span><span />

<span>2) When you integrate you get:
</span><span />

<span>N - No = - kt
</span>
<span></span><span /><span>
3) Half life => N = No / 2, t = t'
</span><span />

<span>=> No - No/ 2 = kt' => No /2 = kt' => t' = (No/2) / k
</span><span />

<span>3) Plug in the data given: No = 0.884M, and k = 5.42x10⁻²M/s
</span>
<span /><span /><span>
t' = (0.884M/2) / (5.42x10⁻²M/s) = 8.15s</span>
6 0
3 years ago
Read 2 more answers
Is a octopus a carnivore or a herbivore
timofeeve [1]
Carnivore, but some are herbivores
4 0
4 years ago
What are the two ways light moves through space? for astronomy the solar system
Mariana [72]

Answer:

The Solar System moves through the galaxy with about a 60° angle between the galactic plane and the planetary orbital plane. The Sun appears to move up-and-down and in-and-out with respect to the rest of the galaxy as it revolves around the Milky Way

Explanation:

Hope you like it

7 0
3 years ago
Read 2 more answers
Choose the answer that best completes the following statement: When an aluminum atom reacts so as to attain a noble gas electron
boyakko [2]

The options

Select one:

a. a 3- ion forms.

b. the noble gas configuration of argon is achieved.

c. the result is a configuration of 1s2 2s2 2p6.

d. the atom gains five electrons.

Answer:

c. the result is a configuration of 1s2 2s2 2p6.

Explanation:

Aluminium atom has atomic number of 13 , hence the number of electron is 13 for a neutral atom of aluminium. When aluminium atom reacts with other elements it usually gives out three electron to attain the octet configuration.

The cation representation of aluminium is Al3+ because it has loss three electron to attain the octet rule. Aluminium will be left with 10 electrons after losing 3 of it electrons. The electronic configuration will be represented as follows after losing three electrons;

1S² 2S² 2P∧6 .

At this stage the octet rule has been achieved as it will be represented as

2  8.  The first energy shell now contains two electron and the second energy shell contains 8 electrons.

The configuration of  Neon has been formed in the process.

4 0
3 years ago
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