Answer:
Answer in explanation
Explanation:
A. This is wrong. The reactants are on the left side of the yields arrow
B. This is wrong. They can only be at one side at a time. They cannot be on both sides at the same time.
C. The products are on the right side of the yields arrow and not at the left side
D. This is correct. The reactants are on the left side of the yields arrow.
E. This is correct. We can have varying numbers of the number of atoms on both side of the yields arrow. The numbers may differ until we decide to balance the equation
Answer: The value of 
for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.
Its solubility product will be as follows.
![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
Cell reaction for this equation is as follows.
Reduction half-reaction: 
, 
Oxidation half-reaction: 
, 
= ?
Cell reaction: 
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product,
= 
Therefore, according to the Nernst equation
![E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%5Cfrac%7B0.0592%20V%7D%7Bn%7D%20log%20%5Cfrac%7B%5BAgCl%5D%7D%7B%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%7D)
At equilibrium, 
= 0.00 V
Putting the given values into the above formula as follows.
![0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}](https://tex.z-dn.net/?f=0.00%20%3D%20E%5E%7Bo%7D_%7Bcell%7D%20-%20%5Cfrac%7B0.0592%20V%7D%7B1%7D%20log%20%5Cfrac%7B1%7D%7B%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%7D)
= 
= 0.577 V
Hence, we will calculate the standard cell potential as follows.
= 0.222 V
Thus, we can conclude that value of for the half-cell reaction is 0.222 V.
NO, It Isn't
Ideally a population in Hardy Weinberg equilibrium should hold true to the following equation for genotypic frequencies of an allele;
P² + 2pq + q² = 1
Explanation:
We are provided with allelic frequencies hence we can derive the genotypic frequencies; (CR allele: p = 0.6 Frequency of the CW allele: q = 0.4)
P² = 0.6 ^2 = 0.36
2pq = 2 * 0.6 * 0.4 = 0.48
q² = 0.4 ^ 2 = 0.16
Lets find out if all add up to as supposed to;
0.36 + 0.48 + 0.16 = 1
Converting to percentages is easy – just multiply by 100
- 36 % CRCR
- 48% CRCW
- and 16 % CWCW
The population provided is not in equilibrium because their percentages vary widely to that the expected Hardy Weinberg's equilibrium percentages. This could be attributed to factors like;
- Migration
- Mutations,
- There is natural selection in progress in the population
- There is gene flow
Learn More:
For more on Hardy Weinberg's equilibrium check out;
brainly.com/question/9916141
#LearnWithBrainly
Like disolves like is the golden rule
