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3 years ago

How many carbon atoms are in 1.25 mol of silver acetate?

Chemistry

1 answer:

Yuri [45]3 years ago

7 0

Im not sure but I did this a long time ago I think its 5.00 mols

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In the equation C3H8 + O2 -> CO2 + H2O, what coefficient belongs in front of the O2 group?

tankabanditka [31]

Answer:

Explanation:

C3H8. + 5O2. ::: 3CO2. + 4H2O

4 0

3 years ago

There are three isotopes of hydrogen H-1, H-2, and H-3 all of these isotopes have

levacccp [35]

There are three isotopes of hydrogen H-1, H-2, and H-3 all of these isotopes have "One Proton"

Hope this helps!

4 0

3 years ago

The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If

Hatshy [7]

$7.7 \times 10^{2} \; \text{K}$ .

<h3>Explanation</h3>

Units of each quantity:

P = 28 atm;
V = 0.045 L;
n = 0.020 mol;

Ideal gas constant:

$R = 0.0820573 \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}$ .

Apply the ideal gas law:

$T = \dfrac{P \cdot V}{n \cdot R} = \dfrac{{\bf 28} \; \text{atm} \times {\bf 0.045} \;\text{L} }{{\bf 0.020}\; \text{mol} \times {\bf 0.0820573} \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}} = {\bf 767.76} \; \text{K}$ .

All data given in this question come with two significant figures. Round the value of T to two significant figures:

$T = 767.76 \;\text{K} = 7.7 \times 10^{2} \; \text{K}$ .

7 0

3 years ago

Read 2 more answers

Which atom has the greatest attraction for the electrons in a chemical bond?

RSB [31]

Answer:

oxygen

Explanation: thats what we need the most

8 0

4 years ago

Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equa

Rufina [12.5K]

Answer : The mass of $O_2$ required is, 61.82 grams.

Explanation :

First we have to calculate the moles of $C_6H_{12}O_6$

$\text{Moles of }C_6H_{12}O_6=\frac{\text{Given mass }C_6H_{12}O_6}{\text{Molar mass }C_6H_{12}O_6}=\frac{58.0g}{180g/mol}=0.322mol$

Now we have to calculate the moles of $O_2$ .

The balanced chemical equation is:

$C_6H_{12}O_6(aq)+6O_2(g)\rightarrow 6H_2O(l)+6CO_2(g)$

From the balanced reaction we conclude that

As, 1 mole of $C_6H_{12}O_6$ react with 6 mole of $O_2$

So, 0.322 moles of $C_6H_{12}O_6$ react with $0.322\times 6=1.932$ moles of $O_2$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

Molar mass of $O_2$ = 32 g/mole

$\text{ Mass of }O_2=(1.932moles)\times (32g/mole)=61.82g$

Therefore, the mass of $O_2$ required is, 61.82 grams.

7 0

3 years ago