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Sergio039 [100]
3 years ago
6

Why are the very lowest mass stars unable to fuse helium in their cores?

Chemistry
1 answer:
Monica [59]3 years ago
8 0
Because they have used most of their energy
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How many moles of H2O are needed to produce 5.6 mol of NaOH?<br> Na2O + H2O --&gt; 2NaOH
navik [9.2K]

Answer: 2.8 moles

Explanation:

The balanced equation below shows that 1 mole of sodium oxide reacts with 1 mole of water to form 2 moles of sodium hydroxide respectively.

Na2O + H2O --> 2NaOH

1 mole of H2O = 2 moles of NaOH

Let Z moles of H2O = 5.6 mole of NaOH

To get the value of Z, cross multiply

5.6 moles x 1 mole= Z x 2 moles

5.6 = 2Z

Divide both sides by 2

5.6/2 = 2Z/2

2.8 = Z

Thus, 2.8moles of H2O are needed to produce 5.6 mol of NaOH

3 0
3 years ago
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antiseptic1488 [7]

Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

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3 years ago
Name the molecule when potassium reacts with chlorine?
Dominik [7]

Answer: Potassium Chloride

Explanation:

4 0
3 years ago
PLEASE HELP! THANK YOU SO MUCH!!!!!!
Bad White [126]
I hope this can help you

3 0
3 years ago
Hello! Id like if someone could tell me this answer, thank you so much!
DaniilM [7]

Answer:

Option D. ZnCl₂ and H₂

Explanation:

From the question given above, the following equation was obtained:

2HCl + Zn —> ZnCl₂ + H₂

Products =?

In a chemical equation, reactants are located on the left side while products are located on the right side i.e

Reactants —> Products

Now, considering the equation from the question i.e

2HCl + Zn —> ZnCl₂ + H₂

The products are ZnCl₂ and H₂ because from our discussion above, we said that products are only located on the right side of chemical equation.

Thus, option D gives the correct answer to the question.

4 0
3 years ago
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