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ELEN [110]
3 years ago
10

you have been given 250.0 mL of an aqueous solution containing 18.7grams of AgNO3. What is the molarity of solution?

Chemistry
1 answer:
Reil [10]3 years ago
8 0

Hey there!:

Molar mass AgNO3 = 169.87 g/mol

Number of moles:

moles of solution = mass of solute / molar mass

moles of solution = 18.7 / 169.87

moles of solution = 0.110084 moles of AgNO3

Volume in liters:

250.0 mL / 1000 => 0.25 L

Therefore:

Molarity = moles of solution / Volume of solution ( L )

Molarity = 0.110084 / 0.25

=> 0.440 M

Hope that helps!

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Magnesium metal (0.100 mol) and a volume of aqueous hydrochloric acid that contains 0.500 mol of HCl are combined and react to c
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Answer:

2.24 L of hydrogen gas, measured at STP, are produced.

Explanation:

Given, Moles of magnesium metal, Mg = 0.100 mol

Moles of hydrochloric acid, HCl = 0.500 mol

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The formation of the product is governed by the limiting reagent. So,

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0.100 mole of Mg on reaction forms 0.100 mole of H_2

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At STP,  

Pressure = 1 atm  

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Volume = ?

Using ideal gas equation as:

PV=nRT

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V is the volume

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T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K  

<u>⇒V = 2.24 L</u>

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