Question

you have been given 250.0 mL of an aqueous solution containing 18.7grams of AgNO3. What is the molarity of solution?

Answer 1

Hey there!:

Molar mass AgNO3 = 169.87 g/mol

Number of moles:

moles of solution = mass of solute / molar mass

moles of solution = 18.7 / 169.87

moles of solution = 0.110084 moles of AgNO3

Volume in liters:

250.0 mL / 1000 => 0.25 L

Therefore:

Molarity = moles of solution / Volume of solution ( L )

Molarity = 0.110084 / 0.25

=> 0.440 M

Hope that helps!